38 is an acute angle and 105 is an obtuse angle
105
105
70
105 over 1 105/100
Let the sides of the smaller triangle be x:- x = (983/3)-105 x = 222 and 2/3 meters or 222.666 .... recurring
Each side of the rhombus will have a length of 105/4 = 26.25 dm
105 = 90 + 15 15 = 30/2 and 30 = 60/2 you can draw 90° Draw segment AB you can draw 90° at A by drawing perpendicular bisector at A draw equilateral triangle on left side of A will give you 60° bisect 60° twice to give 15° so total angle is 90 + 15 = 105°
Since the dimensions of a standard football field are 105 x 68m, and a football field is a rectangle, then 105 + 68 + 105 + 68 = 346, so the perimeter is 346m.
The square root of 105.
38 is an acute angle and 105 is an obtuse angle
It need not be a complex shape. You can have a rectangle with these properties. Just solve the two equations: 2a + 2b = 100 (for the perimeter) ab = 105 (for the area)
49 degrees
It is an obtuse triangle
13squared=8squared+leg squared. 169=64+leg squared. 105=leg squared. leg= the square root of 105
Let the length be known as x: 2(x+4) = 105 2x+8 = 105 2x = 105-8 2x = 97 x = 48.5 Length = 48.5 units
The inside angles of a triangle always add up to 180. So, if you add the two angles you do have (105 + 34 = 139), you can find out the third:180 - 139 = 41