Since you haven't seen fit to tell us problem 2, we'd only be guessing.
5:16
7/(4+7+5) = 7/16 = 43.75%
It is not explicitly stated in the question, but it is assumed that you draw one marble from each bag. In this case, you have unrelated sequential probability, similar to tossing three coins. The answer is 0.53 or 0.125.
The probability is 0.56
Number of different possible choices = 8 + 6 + 9 = 23Number of available successful choices (blue marbles) = 6Probability of success = 6/23 = 0.26087 = 26.087 %(rounded)
The probability of choosing a blue marble is 5 in 15 or 1 in 3. The probability of then choosing a green marble is 5 in 14. (One is missing) Multiply the two probabilities and you get 5 in 42.(P = 0.1190... about 12%).
100%
This is the same as the probability of choosing either a red of a blue marble. There are 5+4 out of 15 ways of doing this. The probability is therefore 9/15 = 3/5.
1/3 or 33%
The probability of choosing a green marble from this jar would be 6/15. You get this answer by adding up the sum of all the marbles.
If one marble is chosen at random, the probability is 6/(4+6+5) = 6/15 = 2/5
There are 16 marbles total and 7 green ones, so the probability is 7/16.
If you pick only one marble from the bag, at random, it can be any one of 26 marbles. Out of these, 5 of the marbles are green. Thus, there are 26 possible outcomes out of which 5 are favourable - to the event that the marble is green. Therefore the probability of a green marble is 5/26. The calculations become more complicated if you consider choosing a green marble in several attempt: it depends on whether or not the marbles are replaced before the next one is picked.
5:16
The probability of drawing a white marble is .46
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
the probability is you'd get a green marble any other color is impossible. So, the probability is certain