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What is the probability of not drawing a green marble?
To calculate the probability of not drawing a green marble, first determine the total number of marbles and the number of green marbles. The probability of not drawing a green marble is then given by the ratio of the number of non-green marbles to the total number of marbles. This can be expressed as: [ P(\text{not green}) = \frac{\text{Number of non-green marbles}}{\text{Total number of marbles}}. ] Without specific numbers, the exact probability cannot be computed.
A box contains 8 green marbles 4 red marbles and 4 purple marbles if you draw a marble at random what is the probability that you will not draw a red marble?
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
A bag contains 5 red marbles 3 blue marbles and 1 green marble. A randomly drawn marble is not blue?
To find the probability of drawing a marble that is not blue, we first calculate the total number of marbles, which is 5 red + 3 blue + 1 green = 9 marbles. The number of marbles that are not blue is 5 red + 1 green = 6 marbles. Therefore, the probability of drawing a marble that is not blue is 6 out of 9, which simplifies to 2/3.
What is the probability of getting a green marble?
To determine the probability of getting a green marble, you need to know the total number of marbles and the number of green marbles specifically. The probability is calculated by dividing the number of green marbles by the total number of marbles. For example, if there are 5 green marbles out of 20 total marbles, the probability would be 5/20, which simplifies to 1/4 or 25%.
What is the probability you will select 2 red marbles if you have 3 red marbles and 1 green marble in a bag You draw 1 marble and without putting it back you draw a 2nd one?
To find the probability of selecting 2 red marbles without replacement, first consider the total number of marbles, which is 4 (3 red and 1 green). The probability of drawing the first red marble is ( \frac{3}{4} ). After drawing the first red marble, there are now 2 red marbles left out of 3 total marbles, making the probability of drawing a second red marble ( \frac{2}{3} ). Therefore, the combined probability of both events is ( \frac{3}{4} \times \frac{2}{3} = \frac{1}{2} ) or 50%.
What is the probability of not drawing a green marble?
To calculate the probability of not drawing a green marble, first determine the total number of marbles and the number of green marbles. The probability of not drawing a green marble is then given by the ratio of the number of non-green marbles to the total number of marbles. This can be expressed as: [ P(\text{not green}) = \frac{\text{Number of non-green marbles}}{\text{Total number of marbles}}. ] Without specific numbers, the exact probability cannot be computed.
What is the theoretical probability of randomly drawing a green marble if there are 5 red marbles 8 blue marbles and 12 green marbles in a bag.?
The theoretical probability of randomly drawing a green marble can be calculated by dividing the number of green marbles by the total number of marbles in the bag. In this case, there are 12 green marbles out of a total of 5 red marbles + 8 blue marbles + 12 green marbles, which is 25 marbles in total. Therefore, the theoretical probability of drawing a green marble is 12/25 or 48%.
A box contains 8 green marbles 4 red marbles and 4 purple marbles if you draw a marble at random what is the probability that you will not draw a red marble?
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
A bag contains 3 blue marbles 7 red marbles and 5 yellow marbles. If Joe picks 1 marble from the bag at random what is the probability that it will be blue?
A bag of marbles contains 13 marbles. 5 Blue, 3 Yellow, 4 Green and 1 Red. Leave all answers as a ratio in lowest terms. 18 points On a single draw, what is the probability of drawing a yellow marble? What is the probability of not drawing a yellow marble? What are the odds in favor of drawing a blue marble? What is the probability of drawing a red or yellow marble? What is the probability of drawing a purple marble? If you had to bet on drawing a marble of a certain color what color would you not choose?
A bag contains 6 red marbles 9 blue marbles and 5 green marbles You withdraw one marble replace it and withdraw another marble What is the probability that you do not draw two green marbles 25 denomo?
Because you are replacing the marbles then it is an independent event. P(1st one is not green) = 1 - P(first green), equally P(2nd one is not green) = 1 - (second green), Thus it reads P(¬G ^ ¬G) = P(¬G) * P(¬G) = 15/20 * 15/20 = 225/400 = 9/16
A bag contains 5 red marbles 3 blue marbles and 1 green marble. A randomly drawn marble is not blue?
To find the probability of drawing a marble that is not blue, we first calculate the total number of marbles, which is 5 red + 3 blue + 1 green = 9 marbles. The number of marbles that are not blue is 5 red + 1 green = 6 marbles. Therefore, the probability of drawing a marble that is not blue is 6 out of 9, which simplifies to 2/3.
What are the odds in favor of choosing a white marble from a bag containing 3 black marbles 4 green marbles and 6 white marbles?
The probability of drawing a white marble is .46
A box contains 3 red marbles 6 blue marbles 12 green marbles and 4 purple marbles if a marble is drawn from the box what is the probability that it is red?
There are a total of 25 Marbles The chances are 3 out of 25 drawing a Red marble. 3/25 = 12% chance of drawing a red marble
What is the probability of drawing 1 green then 1 blue marble from a bag with 5 blue marbles 5 red marbles 3 green marbles 2 white marbles?
hypergeom. f(1;13,3,1) * f(1;12,5,1)
What is the probability of getting a green marble?
To determine the probability of getting a green marble, you need to know the total number of marbles and the number of green marbles specifically. The probability is calculated by dividing the number of green marbles by the total number of marbles. For example, if there are 5 green marbles out of 20 total marbles, the probability would be 5/20, which simplifies to 1/4 or 25%.
What is the probability you will select 2 red marbles if you have 3 red marbles and 1 green marble in a bag You draw 1 marble and without putting it back you draw a 2nd one?
To find the probability of selecting 2 red marbles without replacement, first consider the total number of marbles, which is 4 (3 red and 1 green). The probability of drawing the first red marble is ( \frac{3}{4} ). After drawing the first red marble, there are now 2 red marbles left out of 3 total marbles, making the probability of drawing a second red marble ( \frac{2}{3} ). Therefore, the combined probability of both events is ( \frac{3}{4} \times \frac{2}{3} = \frac{1}{2} ) or 50%.
A bag contains 6 red marbles 7 blue marbles and 6 green marbles If one marble is randomly picked from the bag what is the probability that this is a blue marble?
There would be a 7/19 or 36.84% chance of drawing a blue marble from the bag.
