When you roll a 6 sided die there are 6 possible outcomes. 1,2,3,4,5,6. Out of these 3 are multiples of 2.
Therefore the Probability of getting a multiple of 2 is (3/6) which simplifies to (1/2) or a half.
The answer depends on what numbers are on the faces of the dice.
The theoretical probability of rolling a 5 on a standard six sided die is one in six. It does not matter how many times you roll it, however, if you roll it 300 times, the theoretical probability is that you would roll a 5 fifty times.
I'm assuming you're looking for the probability that you roll either a one or six at least once. So the problem can be rewritten as: 1 - probability of rolling 60 times and never getting ones or sixes = 1 - (2/3)^60
Well, honey, unless that die is rigged or magical, the probability of getting a number greater than 0 when rolling it once is 100%. I mean, unless you manage to roll a negative number or a zero, but then we'd have bigger problems to deal with than just probabilities.
For the first 5 to appear on the tenth roll, the first nine rolls must not be a 5 and the tenth must. Therefore: probability = (5/6)9 x 1/6 ≈ 0.0323 = 3.23 %
1 in 3
It is 1/3.
50%
On a single roll of a fair, six-sided die, it is 1/2.
With a normal 6-sided die the probability would be 2/6, or 1/3.
For a 6 sided die, each number 1 - 6 has equal probability. So, probability of rolling a 5 is 1/6.
Assuming a 6 sided die, a roll of 2 gives a maximum value of 12. So the probability of getting a 16 is zero.
5/36 in a single roll.
The probability is 0.
That depends on what kind of dice you are rolling and how many of them you roll. If you roll two 6-sided dice once, the probability of getting the number 100 is exactly zero. You cannot get a 100 on one roll of two 6-sided dice. Other dice and different numbers of them may yield different probabilities.
The probability of rolling an 8 is Zero.
It is 1/3.