The answer depends on how many dice you are rolling and how many times.
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The probability of rolling a 7 on a pair of 2 dices is: P(7) = 6/36.The probability of rolling a 11 on a pair of 2 dices is: P(11) = 2/36.The probability of rolling 7 or 11 is the sum of both single probabilities:P(7 or 11) = 6/36 + 2/36 = 8/36 = 2/9 = 0.2222... ≈ 22.2%.Explanation.When rolling a pair of fair dice there are 36 possible equiprobable events oroutcomes. They are:(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),(3,1), . . . . . . . . . . . . . . . . . , (3,6),(4,1), . . . . . . . . . . . . . . . . . , (4,6),(5,1), . . . . . . . . . . . . . . . . . , (5,6),(6,1), . . . . . . . . . . . . . . . . . , (6,6).Each of these 36 events has the probability of happening of 1/36.For the case of the sum of both dice to be 7, there are 6 possible outcomes, so theprobability of the event sum equals 7 is: P(7) = 6/36 = 1/6.For the case of the sum of both dice to be 11, there are 2 possible outcomes, (6,5)and (5,6), so the probability of the event sum equals 11 is: P(11) = 2/36 = 1/18.
The probability is 21/36 = 7/12
It is 15/36.
5 over 11
If the first roll is a three, it's impossible to get an eleven (the highest you can get is a 9), so the probability is 0. The way to get a sum of 7 is to add 3 and 4. The probability of getting a 4 on the second die is 1/6. Therefore, by adding the two probabilities of the outcomes (0 and 1/6), you get the answer: 1/6.