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The probability of scoring an exact value for a continuous variable is zero for any value. The probability of scoring 115 (or more) is 15.87%

Q: What is the probability of scoring 115 when mean is 100 and standard deviation is 15?

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The mean and standard deviation do not, by themselves, provide enough information to calculate probability. You also need to know the distribution of the variable in question.

Information is not sufficient to find mean deviation and standard deviation.

Standard deviation can be greater than the mean.

Yes. Consider the definition of the standard deviation. It is the square root of the variance from the mean. As a result, it can be said that the standard deviation is dependent on the mean.

The standard deviation tells us nothing about the mean.

Related questions

with mean of and standard deviation of 1.

The mean and standard deviation do not, by themselves, provide enough information to calculate probability. You also need to know the distribution of the variable in question.

a mean of 1 and any standard deviation

with mean and standard deviation . Once standardized, , the test statistic follows Standard Normal Probability Distribution.

a is true.

The mean deviation (also called the mean absolute deviation) is the mean of the absolute deviations of a set of data about the data's mean. The standard deviation sigma of a probability distribution is defined as the square root of the variance sigma^2,

The probability is 0.5

probability is 43.3%

Intuitively, a standard deviation is a change from the expected value.For the question you asked, this means that the change in the "results" doesn't exist, which doesn't really happen. If the standard deviation is 0, then it's impossible to perform the test! This shows that it's impossible to compute the probability with the "null" standard deviation from this form:z = (x - Âµ)/ÏƒIf Ïƒ = 0, then the probability doesn't exist.

Information is not sufficient to find mean deviation and standard deviation.

The cumulative probability up to the mean plus 1 standard deviation for a Normal distribution - not any distribution - is 84%. The reference is any table (or on-line version) of z-scores for the standard normal distribution.

Mean 0, standard deviation 1.