There are 36 outcomes for rolling 2 dice, and there is 1 way that a 12 can occur which is 6,6. So, the probability of rolling the sum of 12 on 2 dice is 1/36.
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There is one way to roll a sum of 12. There are 36 different outcomes from rolling a pair of dice. Therefore, the probability is 1/36 ~= 0.0278 = 2.78%
The largest possible sum with 2 six sided dice is 12.
The problem can be split into two parts, rolling a 12, or rolling a 4 or less. This can be further broken down to rolling a 2, rolling a 3, rolling a 4, or rolling a 12. P(rolling 4 or less, or 12) = P(rolling 4 or less) + P(rolling 12) = P(rolling a 2) + P(rolling a 3) + P(rolling a 4) + P(rolling a 12) = 1/36 + 2/36 + 3/36 + 1/36 = 7/36
90.47619% Close but no cigar. I presume u r talking about rolling a pair of dice. There are 6 possible outcomes 4 each die, all equally likely, for a total of 36 equally likely possible outcomes. There is only 1 with a sum of 2, and 2 with a sum of 3, for a total of 3 outcomes with a sum of 3 or less. That's 3 out of 36, or 1/12. The other 11/12 represent a sum of more than 3, and that's 91.6666666...%
Of all the six numbers on a cube, only the '5' is not a factor of 12.Probability of rolling a factor of 12 on the first cube = 5/6 .Probability of rolling a factor of 12 on the second cube = 5/6 .Probability of rolling a factor of 12 on both cubes = (5/6 x 5/6 ) = 25/36 = 694/9 %.