1/6·1/6·1/6=(1·1·1)/(6·6·6)=1/216 It should be one DIE, not one DICE. The multiplication sign is shift-option-9.
The total of all sides of three dice = 63
the chances of rolling doubles once is 1 in 6; 3 times in a row it is 1 in 216. It does not make any difference after how many times you rolled the dice before.
Nope - the odds of throwing a six with a single dice - 6:1. For 600 throws with an evenly balanced dice, you should only score a six an average of 100 times.
3 times (out of 36) is the probablility Possible Outcome 1 - Dice 1: 4, Dice 2: 6 Possible Outcome 2 - Dice 1: 5, Dice 2: 5 Possible Outcome 3 - Dice 1: 6, Dice 2: 4
5/216
100/6 = 16.6 times
zero as you only have 3 dice, with the number 6 on them only once on each dice. so if you are lucky you can only throw 6 3 times using 3 dice.
The total of all sides of three dice = 63
50% chance
(1/36)3
1/6 times 1/6 times 1/6= 1/216 chance of getting a 4.
Depends if the dice is bias then you an not have an answer if it is fair then you times 6 by 3 which = 18 so if you want three different outcomes then 3/18 which is simplified to 1/6 of a chance!
The probability that the sum is seven all three times is 1/216.
With one roll of three dice, the probability is 7/8.
The probability of of rolling three ones on three dice is (1 in 6)3, or 1 in 216, or about 0.004630.
the chances of rolling doubles once is 1 in 6; 3 times in a row it is 1 in 216. It does not make any difference after how many times you rolled the dice before.
When rolling three six-sided dice, each die has 6 faces, leading to a total of (6 \times 6 \times 6 = 216) different combinations. This includes all possible outcomes, where the order of the dice matters. If you were looking for unique combinations regardless of order, the calculation would be different, but for standard dice rolls, the total is 216.