If: x+y = 79 Then: y = 79-x If: xy = 1288 Then: x(79-x) = 1288 and it follows that: 79x-x2-1288 = 0 Solving the above quadtratic equation gives x a value of 23 or 56 So the values are x = 23 and y = 56 Check: 23+56 = 79 and 23*56 = 1288
The product is 63,042
1817
79 x 63 = 4,977 -Red Mist
As a product of its prime factors: 2*2*2*79 = 632 or as 23*79 = 632
79 x 23
409,457 = 71 x 73 x 79
144 x 23 = 3312
23 x 56 = 1288
The formula would be: X(X+1)=6162. X^2+X = 6162. X^2+X-6162 = 0; Factor this. (X+79)(X-78)=0. X+79=0 or X=-79; impossible. X-78=0; X=78; first page. Second page X+1=79. Therefore page numbers are 78 & 79. Check: 78*79=6162.
23002,300
In the prime factorisation of a perfect square in power format, all primes must be to an even power. 5688 = 23 x 32 x 79 To convert this it a perfect square, it needs the 2 and 79 to have an even power - the 3 is already at an even power. The smallest way to do this is to multiply 5688 by 2 x 79, ie multiply it by 158. 5688 x 158 = 23 x 32 x 79 x 2 x 79 = 24 x 32 x 792 = (22 x 3 x 79)2 = (948)2 = 898704