If the diameter is 25 then the radius must be 12.5
Formula for sphere volume: 4/3πr³ Plug in 18 for r; the volume is 24429 cm³. Density of iron: 7850 kg/m³ 24429 cm³ • 7850 kg/m³ = 191.76765 kg
for density of steel @ 7850 kg/m3 you can use No of bars (12 m long) per ton = (13500 / D2) where D= bar diameter in mm
7850
Use steel density of 7850 kg / cubic metre, express all dimensions in metres. > volume = 1 * 1 * 0.02 = 0.02 cubic metres, then: 0.02 cubic metres @ 7850 kg / cubic metre = ( 0.02 * 7850 ) 157 kg
The density of steel is 7850kg/m3 so a 1m2 of 1mm sheet would weigh 7850 x 0.001 = 7.85kg
7850 sq ft. Formula is pi x R squared. Diameter of 100 means Radius (r) is 50. 50 squared (multiplied by itself) is 25000. Multiply THAT by the value of pi- or 3.14, and you get 7850 sq ft.
The equation for the area A of a circle is A = pi*r2, where r is the radius of the circle. If you plug in 7850 for the area, you get pi*r2 = 7850. Assuming pi = 3.14, the equation then simplifies to r2 = 7850/3.14 = 2500. Taking the square root of both sides gives you the radius r as 50.
The radius would be 49.987 yards.
Density = mass/volumeThe unit weight of steel is 7850 kg/m3volume of bar = (πd2/4)*Lhence mass = ((πd2/4)*L)*7850= ((3.14 *d2/4)*1)*7850 for unit length= 0.785*d2*7850= 6162.25 d2 if d is in metersor d2 /162 if d is in mm.By putting the value of diameter of rod, you can calculate the unit weight of any size tmt bar.
7850 meters = About 5 miles (4.87776386).
Answer: 7850 acres = 12.2656 mi²
The density of steel is around 7850 kg / m3 therefore to find the weight of the steel rod we need to know it's volume.A rod is more commonly described as a cylinder in geometry which has a volume equal to the following:Pi x r2 x hWherer = radius of cylinder (m)h = height of cylinder (m)Volume = Pi x (0.02 x 0.02) x 1Volume = 0.00125 m3Therefore the mass of the rod = 0.00125 x 7850Mass = 9.81 kgWeight = 9.81 x 9.81Weight of rod = 96.2 Newtons
Density = mass/volumeThe unit weight of steel is 7850 kg/m3volume of bar = (πd2/4)*Lhence mass = ((πd2/4)*L)*7850= ((3.14 *d2/4)*1)*7850 for unit length= 0.785*d2*7850= 6162.25 d2 if d is in metersor d2 /162 if d is in mm.By putting the value of diameter of rod, you can calculate the unit weight of any size tmt bar.
weight = density * volumeUsing steel density @ 7850 kg / cu. metreDimensions in metres>volume = pi * r * r * l = 3.1416 * 0.0125 * 0.0125 * 1.0= 0.00049087 cu.metres>weight = 7850 * 0.00049087 = 3.853 kg
Weight = {(3.1416 (0.025)^2) / 4 }* 7850 kg/m^3 * 1m = 3.85336 kg/.
=3.14 * (Diameter of pipe in Mtr. - wall thickness in Mtr. ) * Wall Thickness in Mtr. * 7850
7850