Mean: 7.5
Media
n: 7.5
Mode:
no
ne
Ra
nge: 7
4, 5, 6, 7, 8, 9, 10, 11
Mean is the average:
(4 + 5 + 6 + 7 + 8 + 9 + 10 + 11)
÷ 8 = 7.5
Media
n is the middle value i
n the list:
But there isno middle
number, so the media
n
is the mea
n of the two middle values:
(7 + 8)
÷ 2 = 7.5
There is
no mode because the
numbers i
n the list appear o
nly o
nce.
Ra
nge is the differe
nce of the largest value a
nd the smallest value: 11 - 4 = 7
mean=19.1 median=18 mode=18 range=10 there are websites all over that help with this stuff just Google how to find mode mean range and median and you will get tons of results
The median is 8.5. The mode is 8. The range is 14.
They quick answer is YES!Here is an example.Before we begin let quickly recap what the we mean by "mean", "median", "mode" and "range":[MEAN] - The sum of all the values, divided by the total number of values.[MEDIAN] - The middle value when the data is arranged in numerical order.[MODE] - The most common value in a data set.[RANGE] - The difference between the highest and lowest values in the set.If we had the following numbers 1, 2, 2, 2, 3,The [MEAN] would be: TWO= 1+2+2+2+3/5 = 10/5 = (2)The [MEDIAN] would be: TWO= 1 2 (2) 2 3 = (2)The [MODE] would be: TWOThe most common value is (2)The [RANGE] would be: TWOrange = (highest - lowest) = (3-1) = (2)Therefore; Mean, Median, Mode and Range = (2)So the Mean, Median, Mode and Range can all be the same number![Answered by F:A:W:B:Y] - (As always, glad to help)
The range is 114, which is the difference between the highest and lowest numbers which are 120 and 6. The median is 15, which is the middle value when they are listed in order. The mode is 10, which is the most frequently occurring number. It occurs 3 times.Range = 114Median = 15Mode = 10.
Mean: 26.33 Median: 29.5 Mode: 10, 35 Standard Deviation: 14.1515 Standard Error: 5.7773
Range: 34 Mean: 21.71 Median: 15 Mode: 10
Range: 25 Mean: 10 Median: 11 Mode: 11, 1
Mean: 11.6 Median: 12 Mode: 10, 12, 15, 16, 5 Range: 11
There cannot be such a set.If the mean is 10, the mode is 6 and the median is 9, the range must be at least 8.5.If the mode is 6, the median is 9 and the range is 8, the mean must be less than 9.8.
Mean: 7.44 Median: 7 Mode: 7 Range: 7
8, 8, 8, 10, 14, 15 The mean is 10.5 The median is 9. The mode is 8. The range is 7.
Mean: 20.2222222 Median: 12 Mode: 11 Range: 79
what i have is mean is 22.2,median which is the middle is 23,range is 26, and mode is 12
mean: 9 ordered sample: 7, 8, 8, 10, 12 median: 8 mode: 8 range: 12 - 7 = 5
mean=19.1 median=18 mode=18 range=10 there are websites all over that help with this stuff just Google how to find mode mean range and median and you will get tons of results
5, 6, 9, 10, & 10
I'm going to guess that's the set (5, 5, 6, 7, 8, 8, 10, 10, 10, 12) Sum: 81 Mean: 8.1 Mode: 10 Range: 7