Range = Maximum - Minimum = 41 - 28 = 13
12
There are infinitely many sets that will satisfy the requirements. Even if restricted to integer values there are many. Two possibilities are: 16, 28, 28, 30, 32, 34 17, 27, 28, 30, 31, 35
29 and 3
29 26 35 29 26 30 26 18 29 19 18 19 18 29 26 20 18 32 16 29 24 21 35 30 29 28 37 39 29 26.34 6.17
120
29
The numbers are 26, 28, 30, 32, 34 and also 28, 29, 30, 31, 32.
Arranged in numerical order, the numbers read: 25 26 26 28 29 30 32 33 35 The median of these numbers is therefore 29.
12
28, 30, 31, 31, 32 Mean: 30.4 Median: 31 Mode: 31 Range: 4
There are infinitely many sets that will satisfy the requirements. Even if restricted to integer values there are many. Two possibilities are: 16, 28, 28, 30, 32, 34 17, 27, 28, 30, 31, 35
To find the maximum, minimum, range, and median of the numbers 28, 17, 45, 32, 29, 28, 14, and 27: The maximum is 45, and the minimum is 14. The range is calculated as maximum minus minimum, which is 45 - 14 = 31. To find the median, we first sort the numbers: 14, 17, 27, 28, 28, 29, 32, 45. Since there are 8 numbers, the median is the average of the 4th and 5th numbers: (28 + 28)/2 = 28.
28+29+30+31+32 = 150
31
28 90625/100,000= 28 3625/4000= 28 145/160= 28 29/32 The answer is 28 29/32
Maximum = 45 Minimum = 14 Range = Max - min = 45 - 14 = 31
You are given the minimum 28 and maximum 34, which means that all the numbers are in the set (28, 29, 30, 31, 32, 33, 34). Since there are fewer than 12 numbers in the set to choose from, there will have to be repeats. You are given the mode 29, which means that 29 appears more often than any other number in the set. The median is 30, which means that half the numbers are above 30 and half are below. There are many different ways to construct a set meeting those conditions. One such set would be (28, 29, 29, 29, 29, 30, 30, 31, 32, 33, 34, 34).