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y = 2sin(x)?
If that's your function, well we know that sin(x) oscillates between y = 1 and y = -1, but in our case we have double that from 2sin(x), so our range is -2 to 2.
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∙ 12y ago
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In the ordered pair x y the value of y is a member of the?
x is a member of the function's domain, y is a member of the function's range.
What is the range of a linear function?
The range is the y, while the domain is the x.
If an inverse function undoes the work of the original function the original functions range becomes the inverse functions?
Maybe; the range of the original function is given, correct? If so, then calculate the range of the inverse function by using the original functions range in the original function. Those calculated extreme values are the range of the inverse function. Suppose: f(x) = x^3, with range of -3 to +3. f(-3) = -27 f(3) = 27. Let the inverse function of f(x) = g(y); therefore g(y) = y^(1/3). The range of f(y) is -27 to 27. If true, then f(x) = f(g(y)) = f(y^(1/3)) = (y^(1/3))^3 = y g(y) = g(f(x)) = g(x^3) = (x^3)^3 = x Try by substituting the ranges into the equations, if the proofs hold, then the answer is true for the function and the range that you are testing. Sometimes, however, it can be false. Look at a transcendental function.
What is the domain and range of the sine function y is equal to 2 sin x?
Domain (input or 'x' values): -∞ < x < ∞.Range (output or 'y' values): -2 ≤ y ≤ 2.
Is y equals x squared -4x plus 3 a domain or range?
Y = x squared -4x plus 3 is an equation of a function. It is neither called a domain nor a range.
What is the period of the function y equals 2sin x?
2 pi
What is the range of the function y equals x?
The function y=x is a straight line. The range is all real numbers.
In the ordered pair x y the value of y is a member of the?
x is a member of the function's domain, y is a member of the function's range.
If tan y equals to x where y is acute find 2 sin y in terms of x?
2sin(y) = 2x/sqrt(1+x^2)
What is the range of a linear function?
The range is the y, while the domain is the x.
What is the second derivative of y equals 2sinx cosx?
y = 2sin(x)cos(x)Use the product rule: uv' + vu' where u is 2sin(x) and v is cos(x) to find first derivative:y' = 2sin(x)(-sin(x)) + cos(x)2cos(x)Simplify:y' = 2cos2(x)-2sin2(x)y' = 2(cos2(x)-sin2(x))Use trig identity cos(2x) = cos2(x)-sin2(x):y' = 2cos(2x)Take second derivative using chain rule:y'' = 2(-sin(2x)cos(2x))Simplify:y'' = -2sin(2x)(2)Simplify:y'' = -4sin(2x)y'' = -4sin(2x)
What is the range of the function y x?
The function y=x is a straight line. The range is all real numbers.The functions just tend to infinity as the x and y values get infinitely large or infinitely small.
If an inverse function undoes the work of the original function the original functions range becomes the inverse functions?
Maybe; the range of the original function is given, correct? If so, then calculate the range of the inverse function by using the original functions range in the original function. Those calculated extreme values are the range of the inverse function. Suppose: f(x) = x^3, with range of -3 to +3. f(-3) = -27 f(3) = 27. Let the inverse function of f(x) = g(y); therefore g(y) = y^(1/3). The range of f(y) is -27 to 27. If true, then f(x) = f(g(y)) = f(y^(1/3)) = (y^(1/3))^3 = y g(y) = g(f(x)) = g(x^3) = (x^3)^3 = x Try by substituting the ranges into the equations, if the proofs hold, then the answer is true for the function and the range that you are testing. Sometimes, however, it can be false. Look at a transcendental function.
How do you find out if y is a function of x?
y is a function of x iffor each value of x (in the domain) there is a value of y, andfor each value of y (in the range) there is at most one value of x.
What is the range of the function y equals -x?
The range depends on the domain, which is not specified.
What is the domain and range of the sine function y is equal to 2 sin x?
Domain (input or 'x' values): -∞ < x < ∞.Range (output or 'y' values): -2 ≤ y ≤ 2.
What is the range of the function y equals -x 2 plus 1?
y < 1
