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What is the rate of effusion of a gas is inversely proportional to the square root of its molar mass?
Wiki User
∙ 12y ago
Graham's law of effusion.
Wiki User
∙ 12y ago
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Root mean square velocity is the measure of the velocity of gas particles that is used for solving problems. It is the square root of the average velocity-squared of the molecules in a gas. The formula for root mean square velocity is sqrt(3RT/Mm) where Mm is the molar mass of the gas in kg / mole, R is the gas constant, and T is the temperature in kelvin.
The molar mass of NaCO3 to four significant figures is what not inscientific notation?
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Molar mass of all oxygen in compound/Total molar mass of compound * 100 = % oxygen in compound ==================
What is the molar mass of CO2 rounded to the nearest whole number?
The answer is simple it's one/1
How to measure the acidity and basicity of a substances?
The pH of a solution is a measure of the molar concentration of hydrogen ions in the solution and as such is a measure of the acidity or basicity of the solution. The letters pH stand for power of hydrogen and numerical value for pH is just the negative of the power of 10 of the molar concentration of H+ ions.
How can you compare the rates of effusion of two gases in a mixture?
The rate of effusion of gases is inversely proportional to the square root of their molar masses. By comparing the molar masses of the two gases, you can determine which gas effuses faster. The gas with the lower molar mass will effuse more quickly.
What is Graham's law of effusion?
Graham's law of effusion states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. In other words, lighter gases effuse or diffuse at a faster rate than heavier gases under the same conditions.
How is the effusion rate of gas related to its molar mass?
The effusion rate of a gas is inversely proportional to the square root of its molar mass. This means that lighter gases effuse faster than heavier gases. This relationship is described by Graham's law of effusion.
Does a lighter gas effuse slower than heavier gases?
No, lighter gases effuse faster than heavier gases. This is because the rate of effusion is inversely proportional to the square root of the molar mass of the gas. Lighter gases have lower molar masses, which results in faster effusion speeds.
What is the rate of effusion of nitrogen compared to oxygen?
The rate of effusion of nitrogen is slightly lower than that of oxygen due to nitrogen being a slightly heavier molecule than oxygen. This is based on Graham's law, which states that the rate of effusion is inversely proportional to the square root of the molar mass of the gas.
Graham's law states that the rate of effusion of a gas is inversely proportional to the square root of the?
molar mass of the gas. This means that lighter gas molecules effuse at a faster rate than heavier gas molecules at the same temperature.
What is the ratio of effusion rates for the lightest gas H2 to the heaviest known gas UF6?
The ratio of effusion rates is inversely proportional to the square root of the molar masses of the gases. The molar mass of H₂ is about 2 g/mol, and the molar mass of UF₆ is around 352 g/mol. Therefore, the ratio of effusion rates for H₂ to UF₆ is approximately √(352/2) which is about 13.3:1.
What gases will effuse the most rapidly chlorine hydrogen ammonia or bromine?
Assuming they are at the same temperature, ammonia will effuse most rapidly due to its lower molar mass compared to the other three gases. Effusion rate is inversely proportional to the square root of molar mass.
What are the variables involve in Graham's law?
The variables involved in Graham's law are the molar mass of the gas particles and the rate of diffusion or effusion of the gas. The rate of diffusion or effusion is inversely proportional to the square root of the molar mass of the gas particles.
How does the rate of effusion of sulfur dioxide SO2 compare to that of helium (He) (Note the molar masses are SO2 64 gmol He 4.0 gmol.)?
The rate of effusion of a gas is inversely proportional to the square root of its molar mass. Helium has a molar mass of 4.0 g/mol, while sulfur dioxide has a molar mass of 64 g/mol. Therefore, the rate of effusion of SO2 will be √(4.0/64) = 1/4 times that of helium. In other words, sulfur dioxide will effuse more slowly than helium.
Does oxygen effuse 1.07 times faster than nitrogen?
No, oxygen does not effuse 1.07 times faster than nitrogen. The effusion rate of a gas is inversely proportional to the square root of its molar mass, so the effusion rate of oxygen would be √(Molar mass of nitrogen / Molar mass of oxygen) ≈ √(28.02 / 32) ≈ 0.91 times faster than nitrogen.
Which gases will have the greatest rate of effusion?
The slowest rate of effusion will be exhibited by the gas with the highest molar mass. For example, Xenon will diffuse at a slower rate than Helium, and chlorine will diffuse at a slower rate than fluorine.
