0.4 m-1 is the ration of surface area 588m2 to volume 1372m3 for a sphere.
The ratio is 300 m2/500 m3 = 0.6 per meter.(Fascinating factoid: The sphere's radius is 5 m.)
First of all, you did not provide measurements for the octagon. Second, surface area is meant for three-dimensional figures. Octagons are two-dimensional.
You don't take the square root of a house, or of any object for that matter. You can take a square root of numbers, and of certain measurements, for example, the house's surface area.You don't take the square root of a house, or of any object for that matter. You can take a square root of numbers, and of certain measurements, for example, the house's surface area.You don't take the square root of a house, or of any object for that matter. You can take a square root of numbers, and of certain measurements, for example, the house's surface area.You don't take the square root of a house, or of any object for that matter. You can take a square root of numbers, and of certain measurements, for example, the house's surface area.
The surface area is 2*(8*11 + 11*3 + 3*8) square inches = 2*(88 + 33 + 24) sq inches = 290 square inches.
The flat surface that goes on and on in all directions has no boundaries. This flat surface is called infinite surface. Accordingly, the answer is that the flat surface that goes on and on in all directions is called an infinite surface.
0.6 is the surface area to volume ratio.
If the diameter is 8.4 m and the height is 9.3 m, then:Total Surface Area = 356.26 m2Volume = 515.38 m3
0.5m-1
Perhaps if you read the question properly, you would not have to ask the question!
0.6 m-1 is the ratio of surface area to volume for a sphere.
It appears to be: 3 to 5
why are photoelectric measurements are so sensitive to the nature of the photoelectric surface
0.4 m-1 (Apex)
-- The ratio of 588 to 1,372 is 0.4286 (rounded) -- A sphere with surface area of 588 has volume closer to 1,340.7 . (rounded)
The ratio is 1/2 square meter per cubic meter.
we do not really know
why are photoelectric measurements are so sensitive to the nature of the photoelectric surface