It look like a Fibonacci sequence seeded by t1 = 2 and t2 = 1. After that the recursive formula is simply tn+1 = tn-1 + tn.
10
(4*10+11+2*12+13+2*14)/10 = 11.6
The answer depends on what the explicit rule is!
140/10 = 14
It look like a Fibonacci sequence seeded by t1 = 2 and t2 = 1. After that the recursive formula is simply tn+1 = tn-1 + tn.
A recursive formula is one that references itself. The famous example is the Fibonacci function: fib(n) := fib(n-1) + fib(n-2), with the terminating proviso that fib(0) = 0 and fib(1) = 1.
(1.0*10^-14)/(1.6*10^-1)= Kb Kb=6.25*10^-14
10
1) Recursive algorithms 2) Basic Principle 3) Analysis
The formula for area of a triangle is A = bh/2 where b is the base and h is the heigth. multipy b x h and then divide by 2 to find the area. Based on the values given, multiply 10 x 14 and then divide by 2: 10 x 14 = 140 / 2 = 70 sq in
write a java program to find factorial using recursive and non recursive
for example "sumNums(12345)" would sum 1+2+3+4+5. the recursive code is just really confusing me. unsigned sumDigits (unsigned n) { . . if (n<10) return n; . . else return n%10 + sumDigits (n/10); }
A recursive definition is any definition that uses the thing to be defined as part of the definition. A recursive formula, or function, is a related formula or function. A recursive function uses the function itself in the definition. For example: The factorial function, written n!, is defined as the product of all the numbers, from 1 to the number (in this case "n"). For example, the factorial of 4, written 4!, is equal to 1 x 2 x 3 x 4. This can also be defined as follows: 0! = 1 For any "n" > 0, n! = n x (n-1)! For example, according to this definition, the factorial of 4 is the same as 4 times the factorial of 3. Try it out - apply the recursive formula, until you get to the base case. Note that a base case is necessary; otherwise, the recursion would never end.
(x+y)/2=7; x+y=14; y=14-x 3=√(xy); xy=9; y=9/x Use substitution: 14-x=9/x; 14x - x2=9; x2 - 14x +9=0 Use the quadratic formula: x=[14±√(196-36)]/2; x=[14±√160]/2; x=[14±4√10]/2 x=7+2√10 or x=7-2√10 If x=7+2√10, then y=14-(7+2√10)=7-2√10 If x=7-2√10, then y=14-(7-2√10)=7+2√10 The first pair's geometric mean is √[(7+2√10)(7-2√10)]=√[72-(2√10)2]=√(49-40)=√9=3. The first pair's arithmetic mean is (7+2√10 +7-2√10)/2=14/2=7 The second pair's geometric mean is √[(7-2√10)(7+2√10)]=√[72-(2√10)2]=√(49-40)=√9=3. The second pair's arithmetic mean is (7-2√10 +7+2√10)/2=14/2=7 That's it!
By Euler's formula for the relationship between the number of Vertices, Faces and Edges of a polyhedron, V + F = E + 2 so 14 + 10 = E + 2 so that E = 22.
If we are talking ratios, then no. 14 to 10 is the same as 14/10 or 7/2. 7/2 is 3.5.