89.1429
0.0433
1491 divided by 23 is 64 with remainder 19.
23.75
10.4
22
1588 divided by 624 equals 2 with a remainder of 340.
78
23.25
It is 22.
Out of every 23 consecutive positive integers, one of them is evenly divisible by 23, one producesa remainder of 1, one produces a remainder of 2, . . . . . , one produces a remainder of 13, . . . . . ,and one produces a remainder of 22.So the probability that a random integer will produce a remainder of 13 is (1/23) = about 4.35% (rounded)
199.913