If you randomly take a positive integer and divide it by 23 what is the probability that the remainder is 13?
Out of every 23 consecutive positive integers, one of them is evenly divisible by 23, one producesa remainder of 1, one produces a remainder of 2, . . . . . , one produces a remainder of 13, . . . . . ,and one produces a remainder of 22.So the probability that a random integer will produce a remainder of 13 is (1/23) = about 4.35% (rounded)