The operation that will always have the result in value of 1 for any nonzero number is Inverse Operation of Multipication.
It isn't. 2 divided by zero has no answer, and is a prohibited operation.
The domain is {-1, 0, 1, 3}.
A) Subtract 6 from 48. If the result less than 6 or 0 you made a mistake. Result is 42. Hence start a counter with a value of 1. B) Subtract 6 from 42. If the result less than 6 or 0 you made a mistake. Result is 36. Hence increment the counter by 1. Now counter value is 2. C) Subtract 6 from 36. If the result less than 6 or 0 you made a mistake. Result is 30. Hence increment the counter by 1. Now counter value is 3. D) Subtract 6 from 30. If the result less than 6 or 0 you made a mistake. Result is 24. Hence increment the counter by 1. Now counter value is 4. E) Subtract 6 from 24. If the result less than 6 or 0 you made a mistake. Result is 18. Hence increment the counter by 1. Now counter value is 5. F) Subtract 6 from 18. If the result less than 6 or 0 you made a mistake. Result is 12. Hence increment the counter by 1. Now counter value is 6. G) Subtract 6 from 12. If the result less than 6 or 0 you made a mistake. Result is 6. Hence increment the counter by 1. Now counter value is 7. H) Subtract 6 from 6. If the result is not 0 you made a mistake. Result is 0. Hence increment the counter by 1. Now counter value is 8. Since we have nothing more to subtract from stop the process. The last value of the counter was 8 and so the quotient is 8.
To take the 2's complement:Take the 1's complement, that is, change each 1 to 0, and each 0 to 1.Add 1 to the result.
A+A*b does not mean A plus Ab the operation signified by "+" is called "or" the operation signified by "*" is called "and" there are four possible outcomes of a+a*b if a=1 and b=1 the result is 1 if a=1 and b=0 the result is 1 if a=0 and b=1 the result is 0 if a=0 and b=0 the result is 0 a+a*b is 1 if a is 1 and a+a*b is 0 if a is 0 regardless of the value of b thus a+a*b=a Q.E.D.
Division by zero is an impermissible operation; the result is undefined.
It means that the logical "AND" operation is done one bit at a time. In other words, the operators are compared one bit at a time, and the corresponding bit in the result will be "1" if both bits in the operands are "1"; in all other cases, the result will be "0".It means that the logical "AND" operation is done one bit at a time. In other words, the operators are compared one bit at a time, and the corresponding bit in the result will be "1" if both bits in the operands are "1"; in all other cases, the result will be "0".It means that the logical "AND" operation is done one bit at a time. In other words, the operators are compared one bit at a time, and the corresponding bit in the result will be "1" if both bits in the operands are "1"; in all other cases, the result will be "0".It means that the logical "AND" operation is done one bit at a time. In other words, the operators are compared one bit at a time, and the corresponding bit in the result will be "1" if both bits in the operands are "1"; in all other cases, the result will be "0".
The operation that will always have the result in value of 1 for any nonzero number is Inverse Operation of Multipication.
Let A,B,C are inputs and Y is the output. A B C Y 0 0 0 0 0 0 1 1 0 1 0 1 0 1 1 1 1 0 0 1 1 0 1 1 1 1 0 1 1 1 1 1 Mind it that Y=A+B+C is a logical operation in our case i.e. OR operation. It's not an arithmetic operation (i.e. not a sum operation).
Operation Petticoat - 1977 Operation Petticoat 1-0 is rated/received certificates of: UK:U
The result is 7.
Operation Petticoat - 1977 Operation Petticoat 1-0 was released on: USA: 4 September 1977
The identity element of a set S, with respect to a binary operation ~ is an element of S, denoted by i such that, for every element x, of S, x~i = i~x = x With the "normal" sets of numbers, if the operation is addition, then the identity element is 0, and the identity property is x + 0 = 0 + x = x If the operation is multiplication, the identity element is 1, and the identity property is x * 1 = 1 * x = x.
Yes. AND operation = f(A,B) = AB = A'f(0,B) + Af(1,B) = A'(0B) + A(1B) = A'0 + AB OR operation - f(A,B) = A+B = A'f(0,B) + Af(1,B) = A'(0+B) + A(1+B) = A'B + A1 NOT operation - f(A) = A' = A'f(0) + Af(1) = A'(1) + A(0)
Check the following table: a b c a+b+c a^b^c 0 0 0 0 0 = 0 0 1 1 1 = 0 1 0 1 1 = 0 1 1 1 0 1 0 0 1 1 = 1 0 1 1 0 1 1 0 1 0 1 1 1 1 1 = So they are equal if the number of ones between a, b, and c is zero or an odd number.
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