The simplest of infinitely many possible solutions, is y = x2
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It's simple. Circulator is device which has a peculiar property that each terminal is connected only to the next clockwise terminal. Consider a 3 port circulator with ports 1,2,3 ( arranged in anti clock wise). As there are 3 ports, order of scattering matrix is 3 X 3. [S]ij i= input applied at port i, j= output taken from port j when input is applied at port 1, we get output from port 3 only. i.e,s11=0,s12=0 when input is applied at port 2, we get output from port 1 only. when input is applied at port 3, we get ouput from port 2 only. hence, scattering matrix is 0 0 s13 S = s21 0 0 0 s32 0
rule of 0 is everythign equalls 0
16-16 = 0
2*2 - 12x +16 =0 4 - 12x +16 =0 -12x + 16 +4 =0 -12x + 20 =0 -12x = -20 x = 1.666666667
Assuming the polynomial is written in terms of "x": It means, what value must "x" have, for the polynomial to evaluate to zero? For example: f(x) = x2 - 5x + 6 has zeros for x = 2, and x = 3. That means that if you replace each "x" in the polynomial with 2, for example, the polynomial evaluates to zero.