Reducing squares 100 = 10² 81 = 9² 64 = 8² 49 = 7² 36 = 6² so next is 25 = 5² ---------------------------------- For the given pattern the nth term (n = 1 to 5) is given by: t(n) = n² - 22n + 121
The next number will be 25 because 5 times 5 = 25
There are a few possibilities, but 100 is the most likely.
These are square numbers. 81 = 9 x 9 64 = 8 x 8 49 = 7 x 7 36 = 6 x 6
It is the squares in decreasing order from 102: 100 = 102 81 = 92 64 = 82 49 = 72 etc So it will continue with 62, 52, 42, ... The nth term is given by tn = (11 - n)2
Reducing squares 100 = 10² 81 = 9² 64 = 8² 49 = 7² 36 = 6² so next is 25 = 5² ---------------------------------- For the given pattern the nth term (n = 1 to 5) is given by: t(n) = n² - 22n + 121
Average= (36+49+64+81+100)/5 =330/5 =66
The next number will be 25 because 5 times 5 = 25
.... 49, 36, 25, 16, 9, 4 and 1
36, 49, 64, 81, 100
To obtain a percentage change, form a fraction from the two numbers involved and multiply the result by 100. The increase is 13 (49 - 36) : based on 36 this gives a percentage increase of : 100 x 13/36 = 36.11% (2dp)
49/36 = 113/36
t(n) = n2
There are a few possibilities, but 100 is the most likely.
No.
These are square numbers. 81 = 9 x 9 64 = 8 x 8 49 = 7 x 7 36 = 6 x 6
It is the squares in decreasing order from 102: 100 = 102 81 = 92 64 = 82 49 = 72 etc So it will continue with 62, 52, 42, ... The nth term is given by tn = (11 - n)2