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There are infinitely many polynomials of order 6 that will give these as the first six numbers and any one of these could be "the" rule. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
The simplest solution, based on a polynomial of order 5 is:
U(n) = (32*n^5 - 440*n^4 + 2360*n^3 - 6010*n^2 + 7133*n - 3070)/5.
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What is the rule of this pattern 3 19 99 499 2499?
4567
What is the rule to the pattern 1 8 27 64 125 work?
That series is the cubes of the counting numbers.
What is the rule that describes this pattern of numbers 2 3 5 7 11 13 17 19 23 29?
It is not a rule as such; those number are the first 10 prime numbers.
What is the pattern rule for 4 5 7 11 19?
One rule for this pattern is to add twice the previous value added 4 + 1 = 5 5 + 2×1 = 5 + 2 = 7 7 + 2×2 = 7 + 4 = 11 11 + 2×4 = 11 + 8 = 19 Continuing the next numbers would be: 19 + 2×8 = 19 + 16 = 35 35 + 2×16 = 35 + 32 = 67 ...
How do you do recursive pattern rule?
a recursive pattern is when you always use the next term in the pattern... for example 4,(x2+1) 9,(x2+1) 19,(x2+1) 39,(x2+1) 79,(x2+1) 159
