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What is the rule for the number pattern 1 6 16 31?
The rule is 5, 10, 15 and so the next number will be 20+31 = 51
What pattern is 3 7 15 31?
You double the number before it and add 1.
What is the rule for this pattern 1-3-2-6-5-15-14-42-41?
multiplication pattern
What is the rule for this pattern 2 6 15 31 56 92?
The pattern at each stage is the addition of a square number of increasing value to the previous term. 1 + 12 = 2 2 + 22 = 6 6 + 32 = 15 15 + 42 = 31 31 + 52 = 56 56 + 62 = 92 The formula for the nth term is, a(n) = n3/3 + n2/2 + n/6 + 1 or it can be written a(n) = 1/6(2n3 + 3n2 + n + 6) So the 7th term = 1/6(686 + 147 + 7 + 6) = 1/6 x 846 = 141 ( = 92 + 72) NOTE : The rule is the same as the sum of the squared numbers plus one. So another way of presenting the formula is, a(n) = 1/6[n(n + 1)(2n + 1)] + 1
What three numbers can add up to 31?
15+15+1=31
What is the rule for the number pattern 1 6 16 31?
The rule is 5, 10, 15 and so the next number will be 20+31 = 51
What is the pattern rule for this pattern 1 4 7 11 15?
Add 3 each time
What pattern is 3 7 15 31?
You double the number before it and add 1.
What is the rule for this pattern 1-3-2-6-5-15-14-42-41?
multiplication pattern
What is the rule of the pattern 1 6 16 31 51?
The gaps are 5, 10, 15, 20, ..... The rule becomes add 5(n-1) to the previous number So that the second number is found by adding 5 times (2-1) to 1 = 5+1 = 6 and the third number is found by adding 5 times (3-1) to 6 = 10+6 = 16 and the fourth number is found by adding 5 times (4-1) to 16 = 15+15 = 31 and so on....
What is the pattern rule for pattern 35-21-1-13-15-34?
One possible rule is: Un = (219n5 - 3755n4 + 24075n3 - 70645n2 + 92166n - 36960)/120 for n = 1, 2, 3, etc
What is the rule for this pattern 2 6 15 31 56 92?
The pattern at each stage is the addition of a square number of increasing value to the previous term. 1 + 12 = 2 2 + 22 = 6 6 + 32 = 15 15 + 42 = 31 31 + 52 = 56 56 + 62 = 92 The formula for the nth term is, a(n) = n3/3 + n2/2 + n/6 + 1 or it can be written a(n) = 1/6(2n3 + 3n2 + n + 6) So the 7th term = 1/6(686 + 147 + 7 + 6) = 1/6 x 846 = 141 ( = 92 + 72) NOTE : The rule is the same as the sum of the squared numbers plus one. So another way of presenting the formula is, a(n) = 1/6[n(n + 1)(2n + 1)] + 1
What is the pattern rule for this pattern 1-3-2-6-5-15-14-42-41?
Start at 1. Multiply by 3. Subtract 1. Multiply by 3. Subtract 1. Repeat this pattern.
What is the rule for this pattern 111359173157?
The rule of this pattern is obfuscated by the omission of spaces, giving the impression that this is the number "111,359,173,157". However, the underlying pattern follows the function of the Fibonacci series, but adding sets of 3 instead of sets of 2. So, 1+1+1=3, 1+1+3=5, 1+3+5=9, 3+5+9=17, 5+9+17=31, 9+17+31=57.
What three numbers can add up to 31?
15+15+1=31
What is the rule to the pattern 1 3 7 15?
Each successive number is the sum of the previous number times 2, plus 1.
What is 31 times 1 half?
It is 15.5 or 15 and a half.
