The gaps are 5, 10, 15, 20, .....
The rule becomes add 5(n-1) to the previous number
So that the second number is found by adding 5 times (2-1) to 1 = 5+1 = 6
and the third number is found by adding 5 times (3-1) to 6 = 10+6 = 16
and the fourth number is found by adding 5 times (4-1) to 16 = 15+15 = 31
and so on....
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Start by adding 7, then add 7x2, then 7x4, then 7x8, etc. 2 + (7x1) = 9 9 + (7x2) = 23 23 + (7x4) = 51 51 + (7x8) = 107 The next number is 219.
The consecutive integers whose sum is 51 are 16, 17, and 18.
Let the numbers be 'm' & 'n' Hence mn = 51 (Multiplication) m + n = -16 (Addition) Algebraically rearrange m = -16 -n Ssubstitute (-16-n) n = 51 -16n - n^2 = 51 n^(2) + 16n + 51 = 0 ( It is now in Quadratic form to solve). Complete the Square (n + 8)^2 - 8^(2) = -51 (n + 8)^2 = -51 + 64 = 13 Square root both sides n + 8 = +/-sqrt(13) n + 8 = +/- 3.60555.... n = -13.60555.... & -4.39444.... Are the two number.
The integers are 16, 17 and 18.
Four examples of irrational numbers are 21/2, 31/2, 51/2 & 71/3