There are 5 elements in the event space if you roll a sum of 8 with 2 dice; 2,6 & 6,2 & 3,4 & 4,3 & 4,4.
11 outcomes if the dice are indistinguishable, 36 otherwise.
1/9 ways. total sample space for the experiment is 36(because you have two dice). and you can get 5 in 4 ways that is (1,4),(4,1),(2,3),(3,2). hence 4/36= 1/9.
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The set of possible outcomes is the set of different ways in which an event might or might not happen. Take a very simple example: If you roll a dice you will roll a 6 or a 5 or a 4 or a 3 or a 2 or a 1. So there are 6 different possible outcomes, all of which are equally probable. If you roll 2 dice at the same time the possible total scores are are from 2 ( a 1 and a 1) to 12 (a 6 and a 6), so there are 11 possible outcomes, but not all equally probable.
If we roll 2 dice simultanosly the sample space consists of 6 rows and 6 col so the answer is 6*6 i.e 36 elements.If we roll 6 dice simultanosly the sample space consists of 36 rows and 36 col so the answer is 36*36 i.e 1296 elements.
There are 5 elements in the event space if you roll a sum of 8 with 2 dice; 2,6 & 6,2 & 3,4 & 4,3 & 4,4.
11 outcomes if the dice are indistinguishable, 36 otherwise.
The sample space of 2 dice is 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12.
Two.
One.
1/9 ways. total sample space for the experiment is 36(because you have two dice). and you can get 5 in 4 ways that is (1,4),(4,1),(2,3),(3,2). hence 4/36= 1/9.
No you can decide if you want to roll one or 2 of the dice.
Partial answer: Assuming that the dice show the numbers 1, 2, 3, ... 14 on each die, and that the question refers to throwing both dice and getting the sum. The smallest sum is 2 and the greatest sum is 28. So the sample space is 2,3,4,...,28.
1, 2, 3, 4, 5, 6
2/12
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