0
9
Still curious? Ask our experts.
Chat with our AI personalities
Ezra
Coach
JordanThe sequence with the nth term 6n-3 can be written as follows: 3, 9, 15, 21, 27, ... Each term can be found by plugging in the value of n into the formula 6n-3. For example, when n=1, the first term is 6(1)-3=3; when n=2, the second term is 6(2)-3=9; and so on. This sequence follows an arithmetic progression with a common difference of 6.
Oh, what a lovely question we have here! To find the sequence, we simply substitute different values for n. So if we start with n = 1, the first term would be 6(1) - 3 = 3. If we continue this pattern, the sequence would be 3, 9, 15, 21, and so on. Just like painting a happy little tree, each term in the sequence builds upon the one before it, creating a beautiful pattern.
Add your answer:
Earn +20 pts
What is the nth term rule if the linear sequence 1,7,13,19,25?
6n-5 is the nth term of this sequence
What is the nth term if the sequence is 32 28 24?
The nth term is (36 - 4n)
What is the nth term of this sequence 3 5 7 9 11?
The nth term of the sequence is 2n + 1.
What is the nth term of 1 2 4 8?
Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.
What is the nth term for 7 11 15 19?
The nth term in this sequence is 4n + 3.
What is the nth term sequence for 3n?
123456789 * * * * * The nth term is 3n
What is the nth term rule if the linear sequence 1,7,13,19,25?
6n-5 is the nth term of this sequence
What are the first 4 terms of the sequence which has the nth term formula?
the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4
What is the nth term for -3052?
A single number, such as -3052 cannot define a sequence and, without a sequence you cannot have an nth term.
What is the nth term if the sequence is 32 28 24?
The nth term is (36 - 4n)
What is the nth term of this sequence 3 5 7 9 11?
The nth term of the sequence is 2n + 1.
What is the nth term of 1 2 4 8?
Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.
nth term of 7.14.21.28.35?
The given sequence (7, 14, 21, 28, 35,....) is an arithmetic sequence where each term increases by 7. The nth term of the given sequence is 7n
What is the nth term for 7 11 15 19?
The nth term in this sequence is 4n + 3.
What is the nth term for the sequence 0 4 12 24 40?
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 4, then 8, then 12, then 16, and so on. This pattern suggests that the nth term can be represented by the formula n^2 + n, where n is the position of the term in the sequence. So, the nth term for the given sequence is n^2 + n.
What is the nth term of 7-10-13-16-19?
The nth term of a sequence is the general formula for a sequence. The nth term of this particular sequence would be n+3. This is because each step in the sequence is plus 3 higher than the previous step.
What is the nth term for 1 7 13 19?
The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.
