Each number in this sequence is twice the previous number. The nth. term is 2n-1.
Each number in this sequence is twice the previous number. The nth. term is 2n-1.
Each number in this sequence is twice the previous number. The nth. term is 2n-1.
Each number in this sequence is twice the previous number. The nth. term is 2n-1.
The nth term is: 3n-7 and so the next number will be 11
3n-2
The given sequence appears to be increasing by 10 each time. To find the nth term, we can use the formula for arithmetic sequences: nth term = first term + (n-1) * common difference. In this case, the first term is 4 and the common difference is 10. Therefore, the nth term for this sequence would be 4 + (n-1) * 10, which simplifies to 10n - 6.
The nth term is (2n - 12).
The 'n'th term is [ 4 - 3n ].
n - 1
The nth term is: 3n-7 and so the next number will be 11
The nth term is: 3n-7 and so the next number will be 11
The nth term is 22n and so the next number will be 5*22 = 110
3n-2
3n-2
1254
1 4 9 is a series of squared numbers. The nth term is [ n squared ]
The sequence 4, 6, 8, 10 is an arithmetic sequence where each term increases by 2. The nth term formula can be expressed as ( a_n = 4 + (n - 1) \cdot 2 ). Simplifying this gives ( a_n = 2n + 2 ). Thus, the nth term of the sequence is ( 2n + 2 ).
The given sequence appears to be increasing by 10 each time. To find the nth term, we can use the formula for arithmetic sequences: nth term = first term + (n-1) * common difference. In this case, the first term is 4 and the common difference is 10. Therefore, the nth term for this sequence would be 4 + (n-1) * 10, which simplifies to 10n - 6.
The nth term is (2n - 12).
The 'n'th term is [ 4 - 3n ].