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The square base of pyramid has a side length of 230 m and the sides of the Pyramid meet the base at an angle which measuresapproximately 60 What is the sum of the height and slant height?
429 m
What would be the formula for the lateral area of a regular pyramid where the base is a square with perimeter p and s is the slant height?
LA = 1/2psnewtest3
What is the slant height VP in the regular pyramid below?
The answer is given below.
How do you find lateral area of a regular square pyramid?
1/2(p)(sh) ~which means~ 1/2 x perimeter x slant height slant height= pathagorean theory= c squared= a squared+b squared
How do you find the slant height of a pyramid with a rectangular base?
If you make a line from the top of the pyramid to the center of the base, you have the height of the pyramid. This meets at the midsegment of a line going across the base. Since the height of a pyramid is perpendicular with the base, get this: the height, a line of 1/2 the length of the base, and the slant height form a right triangle. So, you can use the Pythagorean Theorem! For example, if the base length is 6 and the height of the pyramid is 4, then you can plug them into the Pythagorean Theorem (a squared + b squared = c squared, a and b being the legs of a right triangle and c being the hypotenuse). 1/2 the length of the base would be 6 divided by 2=3. 3 squared + 4 squared = slant height squared. 9+16=slant height squared. 25= slant height squared. Slant height=5 units. You're welcome!
