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Given point (-6 -2) and a slope of 5 what is the equation in slope form?
Point: (-6, -2) Slope: 5 Equation: y = 5x+28
Find the slope of the line: 5x - 5y = 7?
Rewrite the equation in slope intercept form y = m x + b and identify the value of m the slope. 5y = - 5x + 7 y = x - 7/5 The slope is given by the coefficient of x which is 1.
Can you write an equation in standard form for a line satisfying the given conditions through the point 0 and 4 with a slope of 5?
The standard form is: 5x - y + 4 = 0
What is the slope of the line represented by the equation y equals 5x plus 2?
5 and the y intercept is 2
What is the equation of the line that passes through the point -7-3 and is parallel to -5x plus 8y equals 27?
Put the equation of the given line into slope-intercept form. The slope is then the coefficient of x. -5x + 8y = 27. 8y = 5x + 27 y = 5/8 x + 33/8.........so the slope of a parallel line is the same i.e. 5/8 Now use the standard slope-intercept equation , y = mx + c, where m is the slope and c is the y-intercept. Substituting the ordered pair values for x and y, and as m is known - this gives, -3 = 5/8(-7) + c : -3 = -43/8 + c : c = 13/8 The equation of the parallel line is thus, y = 5/8x + 13/8 and multiplying throughout by 8 produces an equivalent equation, 8y = 5x + 11
