Well, isn't that a happy little question! The smallest number that has 3, 4, and 5 as factors is 60. You see, when you multiply 3, 4, and 5 together, you get 60, which means 60 can be divided evenly by 3, 4, and 5. Just like painting a beautiful landscape, numbers can come together in harmony to create something special.
The smallest number that has 3, 4, and 5 as factors is the least common multiple (LCM) of 3, 4, and 5. To find the LCM, we first need to find the prime factorization of each number: 3 = 3, 4 = 2^2, and 5 = 5. Then, we take the highest power of each prime factor that appears in any of the factorizations, which gives us 2^2 * 3 * 5 = 60. Therefore, the smallest number with factors 3, 4, and 5 is 60.
165
144
6. Factors are 1, 2, 3, and 6.
4 : with factors 1, 2 and 4
Logically, the smallest number with 4 different prime factors would have to be the product of the smallest four prime numbers. So the smallest natural number with four different prime factors is 210 (2*3*5*7).
The smallest positive integer is 3.
165
How about 6 whose factors are 1, 2, 3 and 6
165
Well, honey, the smallest number with prime factors 3, 5, 7, and 11 is simply the product of these primes: 3 * 5 * 7 * 11 = 1155. So, there you have it, darling, 1155 is the smallest number you're looking for.
2 and 3 are the smallest prime numbers. So answer is 2^3 * 3^3 = 216
4
If you mean 2, 3 and 7 as factors then the smallest number is 42
Since 3 is prime, the factors are 1 and 3.
36
121
The smallest possible number to get from 3 and 4 as your factors is 12...