To find the second smallest number that has 12345 as factors, we need to consider the prime factorization of 12345, which is 3 x 5 x 823. The smallest number with 12345 as a factor is 12345 itself. The second smallest number would be obtained by multiplying 12345 by the next smallest Prime number after 3 and 5, which is 7. Therefore, the second smallest number with 12345 as factors is 12345 x 7 = 86415.
1,243
1243
12345 but if you can use a decimal, then 0.1234 would be the smallest possible number.
823x15=12345
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60
24,691 is the smallest. 24,691 - 1 = 24,690. 24,690 has factors of 12345 (*2) and 6 (*4,115).
It is 31.
120
1,243
To find the number that, when divided by 23456, leaves a remainder of 12345, we can express the number as ( n = 23456k + 12345 ), where ( k ) is an integer. The smallest positive solution occurs when ( k = 0 ), giving ( n = 12345 ). Therefore, the number is 12345.
1243
12345
12345 but if you can use a decimal, then 0.1234 would be the smallest possible number.
To find the smallest number that has 1, 2, 3, 4 and 5 as factors, you're looking for the least common multiple, or LCM, of those numbers. You can find that by listing the multiples of each number but it's faster to combine their prime factors. You need two twos, a three and a five. 2 x 2 x 3 x 5 = 60
823x15=12345
Since there are only five different digits, a 6-digit number can only be generated if a digit can be repeated. If digits can be repeated, the smallest 6-digit number is 111111.