n=72 satisfies the relation. 2*72 = 12**2, and 3*72 = 6**3. The only question is whether or not that is the smallest integer that will do so.
All perfect squares of which 2n is a factor are of form (2x)**2 = 4x**2, with n= 2x**2. Similarly all perfect cubes of which 3n is a factor are of form (3y)**3 = 27y**3 with n = 9y**3.
So, we need integers x and y such that 2x**2 = 9y**3. If the integers x and y are the smallest that satisfy the equation, then we have the smallest n. It doesn't work for y = 1, or any other odd number. If y = 2, n = 72. There is a number x =6 which satisfies the relation. Since y is smallest possible, then n=72 is the smallest positive integer that satisfies the relation.
63= 9* 7. 9 is already a perfect square, so mulitiply by 7. 7 is your answer.
its 81
The prime factorisation of 248832 is 2¹⁰ × 3⁵ Every perfect square number has a prime factorisation where each prime is to an even power. 2 has an even power 3 has an odd power, so need an extra power → multiple 248832 by 3 which gets (2⁵ × 3³)²
The smallest integer is 11 but there is no smallest number! 0.11 is a smaller number and will give a perfect square. 0.0011 is smaller still, and 0.000011 even smaller. That sequence is endless!
A perfect square is a square of an integer (a whole number).
6.
324
The integer is 26
63= 9* 7. 9 is already a perfect square, so mulitiply by 7. 7 is your answer.
the answer is 144, it is divisible by 1, 4, 9, 16, 36, and 144.
its 81
Only if the integer is a perfect square.
Irrational. The square root of a positive integer is either an integer (that is, if the integer is a perfect square), or an irrational number.
Yes. The square root of a positive integer can only be an integer (if your integer is a perfect square), or an irrational number (if it isn't).
In terms of prime factors, 1008 = 24*32*7 Then since 24 and 32 are perfect squares, all that is required is to make 7q a perfect square and so q = 7.
The prime factorisation of 248832 is 2¹⁰ × 3⁵ Every perfect square number has a prime factorisation where each prime is to an even power. 2 has an even power 3 has an odd power, so need an extra power → multiple 248832 by 3 which gets (2⁵ × 3³)²
The four smallest positive integers are 1, 2, 3, and 4. To find the smallest positive perfect square divisible by these numbers, we first determine their least common multiple (LCM). The LCM of 1, 2, 3, and 4 is 12. The smallest perfect square greater than or equal to 12 is 36, which is (6^2). Thus, the smallest positive perfect square that is divisible by 1, 2, 3, and 4 is 36.