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Presumably this is an equation in the form of:

b+2b-11 = 88

3b = 88+11

3b = 99

b = 33

However, if this was b exponent 2 (squared) or b^2 for the first b, then it is

a quadratic expression.

b^2 + 2b - 11 = 88

b^2 + 2b - 99 = 0

(b+11)(b-9) = 0

B = -11 or 9

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Q: What is the solution for B plus 2b-11 equals 88?
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