(x^2) + 24x + 144 = -9 x = -12
144
You must add (17n + 144).
Im assuming you mean x2 (x squared). This equation will be a quadratic. so... x2+144=-24x subtract -24x from itself and the other side -24x -24x ----------------- x2-24x+144=0 now break it down even further (x-12)(x-12)=0 Now you solve the "mini-equations" x-12=0 x-12=0 +12 +12 +12 +12 --------------------------- x=12 or x=12 hope it helps!!!
3(2) + 24x + 48 = 0 6 + 24x + 48 = 0 24x + 54 = 0 24x + 54 - 54 = 0 - 54 24x = -54 24x/24 = -54/24 x = -9/4 x = -2 1/4
x=-.25.
No real roots.
4x + 7 - 8x = 17-4x + 7 = 17-4x = 24x = -6
144
x2 + 24x +180 = 0 By using the quadratic equation, you can find that x = -12 + 6i or x = -12 - 6i
(x-12)^2= 45 x^2 - 24x + 144 = 45 x^2 - 24x + 99 = 0 Using quadratic formula : (24 +/- (180)^0.5) / 2 In exact terms (using surds) = 12 +/- 3 x (5)^0.5 OR = 18.7 or 5.29
X^2 + 24X = 50 you halve the linear term, square it and add it to both sides X^2 + 24X + 144 = 50 + 144 factor the left side; gather terms on the right (X + 12)^2 = 194 (X + 12)^2 - 194 = 0 so, either 144 is your number, or 194 is. Sounds as a silly question to me as you complete the square to get the vertex of the polynomial. Which is; (12,- 194) = wrong!! Woops! Wrong! Made fudemental mistake! [ (- 12 + 12 ) = 0!! ] So, the vertex is; (- 12, - 194 )