3k-5=7k+73k-7k=7+5-4k=12k=-3
k = 8k + 28Subtract '8k' from each side of the equation:-7k = 28Divide each side by '-7' :k = -4
-6k+7k = 1k or normally k on its own.
7k + 4 + 4k - 9 - 5k (7k + 4k - 5k) + (4 - 9) 6k + -5 6k - 5
k=8k+28 k-8k=28 -7k=28 k=-(28/4) k=-4
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution. The most that you can do is: 13p = 31-7k so that p = (31-7k)/13
3k-5=7k+73k-7k=7+5-4k=12k=-3
26-7k=6k First, add 7k to get k on one side. 26-7k+7k=6k+7k 26=13k Divide both sides by 13 to get k by itself. 26/13=13k/13 2=k The answer is 2.
To solve an equation, use the order of operations in reverse:7k-52 = 9(addition)7k = 61(division)k = (61/7) or ~8.71
35k2 - 22k + 3 = 0 35k2 - 15k - 7k + 3 = 0 5k(7k - 3) - (7k - 3) = 0 (5k - 1)(7k - 3) = 0 5k -1 = 0 or 7k - 3 = 0 5k = 1 or 7k = 3 k = 1/5 or k = 3/7
No because 0 is additive inverse the multiplicative inverse of a number is when you multiply that number by the m. inverse and still get that number.
It is: 7k
7k+3 where k is the divisor, an integer greater than 3.
Same as subtracting 6 from 7 = K
It simplifies to 7k = 49 which gives k = 7.
7k = 7,000,000 rupees.
k + 6k - 13 = 177k = 30k = 30/7k = 4.2857