-1
x = y = 3
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
y=(-1) x=(2)
x - 2y = -4 2x - y = 1 To solve this system of equations, I used matrices, and got x = 2 and y = 3.
Equations with the same solution are called dependent equations, which are equations that represent the same line; therefore every point on the line of a dependent equation represents a solution. Since there is an infinite number of points on a line, there is an infinite number of simultaneous solutions. For example, 2x + y = 8 4x + 2y = 16 These equations are dependent. Since they represent the same line, all points that satisfy either of the equations are solutions of the system. A system of linear equations is consistent if there is only one solution for the system. A system of linear equations is inconsistent if it does not have any solutions.
x = y = 3
x = 1 and y = 2
{-1,-2}
Check your text book for how to solve it.
A pair of simultaneous equations in two unknowns which are inconsistent - in the sense that there is no solution that simultaneously satisfies both equations. Graphically, the equations are those of two parallel lines (slope = 2). Since, by definition, they cannot meet there is no solution to the system.
the system of equations 3x-6y=20 and 2x-4y =3 is?Well its inconsistent.
2x - y = 15 2x + 3y = -21 As you observe both equations (having different slopes), you see that the system is consistent, and it has only one solution.
That system of equations has no solution. When the two equations are graphed, they turn out to be the same straight line, so there's no such thing as a single point where the two lines intersect. There are an infinite number of points that satisfy both equations.
The two equations are linear.
There is only one equation, so it's not a system of equations.
There are two solutions and they are: x = -1 and y = 3
There is no solution for those equations because the lines are parallel so, they never touch.