2X^2 - 11X - 21 = 0
X = -b +/- sqrt(b^2 -4ac)/2a
a = 2
b = - 11
c = - 21
X = -(-11) +/- sqrt[(-11)^2 - 4(2)(-21)]/2(2)
X = [11 +/- sqrt( 289)]/4
X = [11 +/- 17]/4
X = 7
X = - 3/2
My TI-84 graphs original equation and confirms answers
The quadratic formula is used to solve the quadratic equation. Many equations in which the variable is squared can be written as a quadratic equation, and then solved with the quadratic formula.
When an equation cannot be solved for "x" to find the zeroes, the quadratic formula can be used instead for the same purpose.
Completing the square is one method for solving a quadratic equation. A quadratic equation can also be solved by factoring, using the square roots or quadratic formula. Solving quadratic equations by completing the square will always work when solving quadratic equations-You can also use division or even simply take a GCF, set the quantities( ) equal to zero, and subtract or add to solve for the variable
This quadratic equation can be solved by three methods: (a) factoring (b) completing the square (c) using the quadratic equation formula.Factoring:25x2+20x+4 = 0(5+2)(5x+2) = 0Solution: x = -2/5 also x = -2/5 (they both have equal roots)
Here are two ways to know if a given quadratic equations can be factored (can be solved by factoring). 1. Calculate the Discriminant D = b^2 - 4ac. When D is a perfect square (its square root is a whole number), then the given equation can be factored. 2. Solve the equation by using the new Diagonal Sum method (Amazon e-book 2010). This method directly finds the 2 real roots without having to factor the equation. Solving usually requires fewer than 3 trials. If this method fails to get the answer, then we can conclude that the equation can not be factored, and consequently the quadratic formula must be used.
A quadratic equation normally has 2 solutions and can be solved by using the quadratic equation formula.
The quadratic formula is used to solve the quadratic equation. Many equations in which the variable is squared can be written as a quadratic equation, and then solved with the quadratic formula.
It is a quadratic equation that can be solved by using the quadratic equation formula whereas x = -9.321825 or x = 0.321825 both given to 6 decimal places
x = 9/2 or x = -2 Solved by using the quadratic equation formula.
The discriminant
It can be solved by using the quadratic equation formula.
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
It can't be solved because the discriminant of the given quadratic equation is less than zero meaning it has no real roots.
It is a quadratic equation and when solved it has equal roots of 3/2 or 1.5
A quadratic equation can be solved by completing the square which gives more information about the properties of the parabola than with the quadratic equation formula.
at first the first person to solve the quadratic equation is from the middle kingdom of Egypt. Greeks were also able to solve the quadratic equation but that was on the unproper way. Greeks were able to solve the quadratic equation by geometric method or equlid's method. equlid's method contains only three quadratic equation. dipohantus have also solved the quadratic equations but he have solved by giving only two roots any they both were only of positive signs.After that arbhatya also gave the two formulas for quadratic equation but the bentaguptahave only accepted only one of them after theat some of the Indian mathematican have also solved the quadratic equation who gave the proper definations and formula and in this way quadratic equation have been formed. Prabesh Regmi Kanjirowa National School
No. It is a linear equation (y = 5/2 x + 5). A quadratic equation requires a squared term, for example y = x2 + 5x + 6; this can be solved for x given y = 0, as in solving x2 + 5x + 6 = 0.