Square root of 25 = +or- 5 Square root of -36 = +or- 6i where i is the imaginary number such that i^2=-1 Square root of 121 = +or-11 So the 8 possible answers are: -16-6i, -16+6i, -6-6i, -6+6i, 6-6i, 6+6i, 16-6i and 16+6i
11 units. (It is the square root of 121, and A=S^2 => 121=S^2 => S=11.)
16(square root)15
The square root of -16 is: 4 i
The square root of 16 is 4
Could be +6, -6, +16, or -16.
Square root of 25 = +or- 5 Square root of -36 = +or- 6i where i is the imaginary number such that i^2=-1 Square root of 121 = +or-11 So the 8 possible answers are: -16-6i, -16+6i, -6-6i, -6+6i, 6-6i, 6+6i, 16-6i and 16+6i
11 units. (It is the square root of 121, and A=S^2 => 121=S^2 => S=11.)
it is impossible to get the square root of a negative, since the definition of a square root is something times itself. example: the square root of 16 is 4 because 4 x 4 = 16. and a negative times a negative is a positive, so the square root of a negative is impossible. however, you can do the square root of 121 (which is 11) and make the 11 a negative. 11 x 11 = 121 and -11 x -11 = 121 but you could make 11 negative after the fact, if that is what you wanted to do.
The square root of the fraction 16 over 169 is 4 over 13.
4 over square root of 16 simplifies to 1 !
Take the square root of the square root of the number (that is the fourth root of the number), for example: √√16 = √(√16) = √4 = 2 24 = 16 ⇒ 2 is the fourth root of 16.
No.
The square root of (any number that isn't a perfect square) is irrational.
4i over 3
41
121