Could be +6, -6, +16, or -16.
The answer is 0.
[ sqrt(-25) / sqrt(9) ] - [ sqrt(-1) ] = j5/3 - j1 = j 2/3
The square root of 25 is 5.
41
The square root of 36 is 20% more than the square root of 25.
Yes, the square root of 121 is 11
121: ± 11625: ± 25
The answer is 0.
Well, butter my biscuit, that's an easy one! The square root of 121 is 11, and since 121 is a perfect square, the square root of 121 is also 11. So, technically, 11 + 11 equals 22. Math can be a real hoot sometimes!
If you mean 36 minus 25 then the square root of 11 is an irrational number
The square root of any negative number is equal to the square root of its absolute value followed by i - an imaginary number representing the square root of minus one. Therefore, such that sqrt(25) = 5, sqrt(-25) = 5i.
Yes. The first is -5, the second is 5i (sqrt 25 x sqrt -1).
Square root of 25 = +or- 5 Square root of -36 = +or- 6i where i is the imaginary number such that i^2=-1 Square root of 121 = +or-11 So the 8 possible answers are: -16-6i, -16+6i, -6-6i, -6+6i, 6-6i, 6+6i, 16-6i and 16+6i
29.5
X2+5x-6. a=1, b=5, and c=-6 The formula is: -b plus or minus the square root of b squared minus 4ac all over 2a. -b+square root of b2-4ac ---- 2a -5 plus or minus the square root of 5 squared minus 4(1)(-6) -5 plus or minus the square root of 25-4(-6) -5 plus or minus the square root of 25+24 -5 plus or minus the square root of 49 -5 plus or minus 7 Here is where you split into two different answers: Number 1: -5 plus 7= 2 Number 2: -5 minus 7= -12 Your answer is X=2, -12
[ sqrt(-25) / sqrt(9) ] - [ sqrt(-1) ] = j5/3 - j1 = j 2/3
sqrt(25) - 9 = 5 - 9 = -4sqrt(25 - 9) = sqrt(16) = +4 and -4