The answer is 0.
[ sqrt(-25) / sqrt(9) ] - [ sqrt(-1) ] = j5/3 - j1 = j 2/3
The square root of 25 is 5.
41
The square root of 36 is 20% more than the square root of 25.
Yes, the square root of 121 is 11
121: ± 11625: ± 25
The answer is 0.
Well, butter my biscuit, that's an easy one! The square root of 121 is 11, and since 121 is a perfect square, the square root of 121 is also 11. So, technically, 11 + 11 equals 22. Math can be a real hoot sometimes!
If you mean 36 minus 25 then the square root of 11 is an irrational number
Square root of 25 = +or- 5 Square root of -36 = +or- 6i where i is the imaginary number such that i^2=-1 Square root of 121 = +or-11 So the 8 possible answers are: -16-6i, -16+6i, -6-6i, -6+6i, 6-6i, 6+6i, 16-6i and 16+6i
The square root of any negative number is equal to the square root of its absolute value followed by i - an imaginary number representing the square root of minus one. Therefore, such that sqrt(25) = 5, sqrt(-25) = 5i.
Yes. The first is -5, the second is 5i (sqrt 25 x sqrt -1).
29.5
X2+5x-6. a=1, b=5, and c=-6 The formula is: -b plus or minus the square root of b squared minus 4ac all over 2a. -b+square root of b2-4ac ---- 2a -5 plus or minus the square root of 5 squared minus 4(1)(-6) -5 plus or minus the square root of 25-4(-6) -5 plus or minus the square root of 25+24 -5 plus or minus the square root of 49 -5 plus or minus 7 Here is where you split into two different answers: Number 1: -5 plus 7= 2 Number 2: -5 minus 7= -12 Your answer is X=2, -12
[ sqrt(-25) / sqrt(9) ] - [ sqrt(-1) ] = j5/3 - j1 = j 2/3
sqrt(25) - 9 = 5 - 9 = -4sqrt(25 - 9) = sqrt(16) = +4 and -4