-3 times the square root of 158 3 times the square root of 158
Seeing as the area = 158 = the length of 1 side squared. One side = the square root of 158 = about 12.5698 feet
The 8th root
The principal square root is the non-negative square root.
To simplify the square root of 5 times the square root of 6, you can multiply the two square roots together. This gives you the square root of (5*6), which simplifies to the square root of 30. Therefore, the simplified answer is the square root of 30.
158
-3 times the square root of 158 3 times the square root of 158
No. If the square root is not an integer, it does not qualify.
sqrt(158) = -12.5698 and 12.5698 approx.
13
Seeing as the area = 158 = the length of 1 side squared. One side = the square root of 158 = about 12.5698 feet
If it is, then its square root has more than 7 decimal places. It's definitely not the square of an integer: (158)2 = 24,964 (159)2 = 25,281 sqrt(25,036) = 158.227684+
The square root of the square root of 2
The 8th root
square root of (2 ) square root of (3 ) square root of (5 ) square root of (6 ) square root of (7 ) square root of (8 ) square root of (9 ) square root of (10 ) " e " " pi "
There are infinitely many of them. They include square root of (4.41) square root of (4.42) square root of (4.43) square root of (4.44) square root of (4.45) square root of (5.3) square root of (5.762) square root of (6) square root of (6.1) square root of (6.2)
It's not a square if it has no root. If a number is a square then, by definition, it MUST have a square root. If it did not it would not be a square.