The square root of 9 is 3, and the square root of 16 is 4. Adding these together, 3 + 4 equals 7. Therefore, the square root of 9 plus 16 is 7.
x²+6x+9=49 x²+6x-40=0 x1=-6/2 - Square root of ((6/2)²+40) x1=-3 - 7 x1= -10 x2=-6/2 + Square root of ((6/2)²+40) x2=-3 + 7 x2= 4
Plus or minus 3i.
well, the square root of 81 is 9, and seven squared is 49, so it wud be 40
3 is the square root of 9
The answer is 0.
sqrt(4) = 2 sqrt(9) = 3 Therefore, the square root of 4 plus the square root of 9 is equal to 2 + 3 = 5.
3+14 = 17
The square root of 9 is 3, therefore 3 + 7 = 10
The square root of 9 is 3, and the square root of 16 is 4. Adding these together, 3 + 4 equals 7. Therefore, the square root of 9 plus 16 is 7.
square root of 81 is 9...and plus 32 is 41.so the answer is 41
Well, butter my biscuit, that's an easy one! The square root of 121 is 11, and since 121 is a perfect square, the square root of 121 is also 11. So, technically, 11 + 11 equals 22. Math can be a real hoot sometimes!
x²+6x+9=49 x²+6x-40=0 x1=-6/2 - Square root of ((6/2)²+40) x1=-3 - 7 x1= -10 x2=-6/2 + Square root of ((6/2)²+40) x2=-3 + 7 x2= 4
9
1 plus (6 divided by ((square root of 9) plus (square root of 9))) or 9/(9-6)-1=2
the square root of 9 is 3 so 1 +3 = 4
if x is equal to the square root of 81 then x is ±9 (plus or minus 9)