56 = 2^3 * 7
√56 = √(4*14) = √4*√14 = 2√14
This is as simplified as it can be while still being an exact answer. It is approximately 7.483 in decimal form.
"7" is the number because its square root is "49" & 49+7=56
7-8
The answer would be 56. You would square root 3136 which would give you 56.
The square roots of 56 are approx -7.5 and +7.5. So any consecutive pair from [-7, +7] will do.
The cube root of -56 = -3.825862
The square root of 3136 is 56.
The square root of 56 is irrational. This is because 56 can be expressed as 4 times 14, and while the square root of 4 is rational (2), the square root of 14 is not a perfect square and is therefore irrational. Thus, the combined result of √56 remains an irrational number.
No, the square root of 56 is not an integer. The square root of 56 can be simplified to 2√14, which is an irrational number. Since it cannot be expressed as a whole number, it does not qualify as an integer.
Square root of 56 = Square root of (4 x 14) = (Square root of 4) x (Square root of 14) = 2 x (Square root of 14) The actual value would be 2 x 3.741 = 7.482
2 square root of 14
sqrt(56) = 7.483 approx.
± 7.483315
56
Root 56 = 7.483314773547882 = 7.48
square root of 3136, square root 3146 56x56
in decimal form the answer is 18.7082869
"7" is the number because its square root is "49" & 49+7=56