For the dataset {26, 30, 34, 38, 42, 46, 50}:
n = 7
Σx = 266
Σx² = 10556
µ = 1/n Σx
σ = √(1/n Σ(x - µ)²) = √(1/n Σx² - (1/n Σx)²)
→ σ = √(1/7 × 10556 - (266/7)²) = √(1508 - 38²) = √64 = 8.
One standard deviation for one side will be 34% of data. So within 1 std. dev. to both sides will be 68% (approximately) .the data falls outside 1 standard deviation of the mean will be 1.00 - 0.68 = 0.32 (32 %)
12
84% To solve this problem, you must first realize that 66 inches is one standard deviation below the mean. The empirical rule states that 34% will be between the mean and 1 standard deviation below the mean. We are looking for the prob. of the height being greater than 66 inches, which is then 50% (for the entire right side of the distribution) + 34%
28
The median is 26.
The standard deviation of 20 22 26 28 34: σ=5.4772
The standard deviation of a single value, such as 34, is not defined in the traditional sense because standard deviation measures the spread of a set of data points around their mean. If you have a dataset that consists solely of the number 34, the standard deviation would be 0, since there is no variation. However, if you're referring to a dataset that includes 34 along with other values, the standard deviation would depend on the entire dataset.
15.72683482 is the standard deviation for that set of numbers.
49.30179172 is the standard deviation and 52 is the mean.
One standard deviation for one side will be 34% of data. So within 1 std. dev. to both sides will be 68% (approximately) .the data falls outside 1 standard deviation of the mean will be 1.00 - 0.68 = 0.32 (32 %)
The factors of 26 are: 1, 2, 13, 26.The factors of 30 are: 1, 2, 3, 5, 6, 10, 15, 30.The factors of 34 are: 1, 2, 17, 34.The common factors are: 1, 2
Compute the variance (or its square root , standard deviation) of each of the data set. Set 1: standard deviation = 10.121 Set 2: standard deviation = 12.09 Set 2 shows more variation around the mean. Check the link below
-34
the median of 24, 26, 27, 27, 29, 30, 33, 34, 36, is... 29 :)
12
84% To solve this problem, you must first realize that 66 inches is one standard deviation below the mean. The empirical rule states that 34% will be between the mean and 1 standard deviation below the mean. We are looking for the prob. of the height being greater than 66 inches, which is then 50% (for the entire right side of the distribution) + 34%
34-26-39