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For the dataset {26, 30, 34, 38, 42, 46, 50}:

n = 7

Σx = 266

Σx² = 10556

µ = 1/n Σx

σ = √(1/n Σ(x - µ)²) = √(1/n Σx² - (1/n Σx)²)

→ σ = √(1/7 × 10556 - (266/7)²) = √(1508 - 38²) = √64 = 8.

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Q: What is the standard deviation of 26 30 34 38 42 46 50?
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