For the dataset {26, 30, 34, 38, 42, 46, 50}:
n = 7
Σx = 266
Σx² = 10556
µ = 1/n Σx
σ = √(1/n Σ(x - µ)²) = √(1/n Σx² - (1/n Σx)²)
→ σ = √(1/7 × 10556 - (266/7)²) = √(1508 - 38²) = √64 = 8.
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One standard deviation for one side will be 34% of data. So within 1 std. dev. to both sides will be 68% (approximately) .the data falls outside 1 standard deviation of the mean will be 1.00 - 0.68 = 0.32 (32 %)
12
84% To solve this problem, you must first realize that 66 inches is one standard deviation below the mean. The empirical rule states that 34% will be between the mean and 1 standard deviation below the mean. We are looking for the prob. of the height being greater than 66 inches, which is then 50% (for the entire right side of the distribution) + 34%
28
The median is 26.