The question cannot be answered since there are not 1296 combinations of 4 dice, only 126. In a combination, the order of the numbers does not matter, so 2355 is the same as 5235 or 3525 etc.
The least error prone way of doing this is to draw a 6x6 square of all the possiblities when rolling a pair of dice, where one is red and one blue, and work out the proportion of the combinations that sum to 7.
since rolling a dice can give you 36 possible combinations, there are 1/9 chances that you will get a sum of 5. 1+4 2+3 3+2 4+1 the 4 equations above will produce a sum of 5 so,the probability is 4/36, or 1/9.
Find the possible combinations of rolling a six with two dice: 1 + 5 = 6 5 + 1 = 6 2 + 4 = 6 4 + 2 = 6 3 + 3 = 6 3 + 3 = 6 Six in total. Find the number of possible combinations; Number of Sides on the Dice (6) to power of how many dice (2) = 36 Number of Times the Dice will sum to Six (6 times) -------------------------------------------------- Number of Possible outcomes This will give us 6 out of 36 rolls. Or reduced 1/6 rolls
The largest possible sum with 2 six sided dice is 12.
Opposite sides of a dice add up to 7
There are 8 different combinations.There are 145 permutations that total 14.Not asked, but answered for completeness sake; there are 1296 possible permutations of four dice, making the probability of a sum of 14 being 145 in 1296 or about 0.1119.
It is 20/1296 = 0.01543 (approx).
Te probability of rolling a sum of 7 with two fair dice is 6 in 36, or 1 in 6, or about 0.1667.Of all the possible combinations of two dice, the sum of 7 has the highest probability, with the other combinations decreasing down to 2 and 12, with probabilities of 1 in 36, or about 0.0278.
The probability that the sum of two dice is 7 is 6 in 36, or 1 in 6.Of all the combinations, this is the one with the highest probability.
To find the number of ways to make a sum of 9 with three dice, we can list the possible combinations of the dice rolls. The combinations of rolls that yield a total of 9 include (3,3,3), (1,3,5), (1,4,4), (2,2,5), and others. By systematically counting all unique combinations and accounting for permutations, the total number of ways to achieve a sum of 9 with three six-sided dice is 25.
25
To find the probability of rolling a sum of six followed by a sum of eight with two six-sided dice, we first calculate each individual probability. The probability of rolling a sum of six is 5/36, and the probability of rolling a sum of eight is 5/36 as well. Since these events are independent, we multiply the probabilities: (5/36) * (5/36) = 25/1296. Thus, the probability of rolling a sum of six followed by a sum of eight is 25/1296.
The least error prone way of doing this is to draw a 6x6 square of all the possiblities when rolling a pair of dice, where one is red and one blue, and work out the proportion of the combinations that sum to 7.
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.
Assuming of course that we are talking about cubic dice. combinations that make 9: 6&3, 5&4, 4&5, 3&6. There are 4 combinations that make 9. There are 36 possible combination of two dice. So 4/36 is 1/9
33,33333...%
When rolling three six-sided dice, the possible sums range from 3 (1+1+1) to 18 (6+6+6). The sums can include every integer from 3 to 18, resulting in a total of 16 different possible sums. Each sum can be achieved through various combinations of the three dice, with some sums having more combinations than others.