There are 3 whose sum is 45 whose sum is 57 whose sum is 69 whose sum is 711 whose sum is 813 whose sum is 915 whose sum is 1017 whose sum is 1119 whose sum is 1219 whose sum is 1317 whose sum is 1415 whose sum is 1513 whose sum is 1611 whose sum is 179 whose sum is 187 whose sum is 195 whose sum is 203 whose sum is 211 whose sum is 22.
The answer to an addition problem is called the sum.The sum of 2 plus 2 is 4.
the sum the sum
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
The sum of their squares is 10.
1605 + 1219 + 1119 + 1153 = 5,096
1605+121911191153______5096 That's it I think.
5093
There are 3 whose sum is 45 whose sum is 57 whose sum is 69 whose sum is 711 whose sum is 813 whose sum is 915 whose sum is 1017 whose sum is 1119 whose sum is 1219 whose sum is 1317 whose sum is 1415 whose sum is 1513 whose sum is 1611 whose sum is 179 whose sum is 187 whose sum is 195 whose sum is 203 whose sum is 211 whose sum is 22.
The easiest way to calculate this is to use the facts thatthe sum of the interior and exterior angles is 180o; andthe sum of the exterior angles of any polygon is 360o.For a regular polygon, each exterior angle will be 360o divided by the number of sides. The interior angle is then 180o - the exterior angle.For a 31-gon:exterior_angle = 360° ÷ 31= 1119/31o⇒ interior_angle = 180° - 1119/31o= 16812/31°≈ 168.39oUse the Interior Angle Formula directlyThe sum of interior angles for a polygon of n sides is (n-2) x 180° and individual angles for a regular polygon will be (n-2) 180°/nPlugging in the value n=31, we have one angle = 29(180)/31 = 168.39°
A shape does not have a sum. The angles of a shape have a sum, the lengths of its sides have a sum, the number of its diagonals are a sum, but the shape itself certainly does not have any sum!
Their sum is 1.Their sum is 1.Their sum is 1.Their sum is 1.
Sum = Sum + first number Sum = Sum + second number Sum = Sum + third number Average = 1/3 x Sum
The answer to an addition problem is called the sum.The sum of 2 plus 2 is 4.
the sum the sum
sum=360
to print the sum of first ten numbers:- void main() {int i,sum; sum=0; while(i<=10) sum=sum+i; i=i+1; } printf("The sum is : %d",sum); }