To solve this problem, we first calculate the sum of 24 and 7, which is 31. Then, we find the difference between 18 and 6, which is 12. Finally, we multiply these two results together: 31 x 12 = 372. Therefore, the product of the sum of 24 and 7 multiplied by the difference of 18 and 6 is 372.
The product of a sum and a difference with 31 times 29 is:(30+1) x (30-1)sum to differencemakea product= 30² - 1²= 900 - 1= 899
Is the sum 31
31 and 18
53 and 22..
To solve this problem, we first calculate the sum of 24 and 7, which is 31. Then, we find the difference between 18 and 6, which is 12. Finally, we multiply these two results together: 31 x 12 = 372. Therefore, the product of the sum of 24 and 7 multiplied by the difference of 18 and 6 is 372.
31
Factors of 25: 1, 5, 25 Their sum = 31 Difference between 31 and 8 = 23.
2, 7 AND 31
2n + (n - 7) = -31 - n3n - 7 = -31 - n3n + n + 7 - 7 = -31 + 7 + n - n4n = -244n/4 = -24/4n = -6Check:2n + (n - 7) = -31 - n2(-6) + [(-6) - 7) =? -31 - (-6)-12 + [-6 + (-7)] =? -31 + 6-12 + (-13) =? -25-25 = -25 True
The numbers 40.5 and 36.5 have a difference of 4 and a sum of 77.
The product of a sum and a difference with 31 times 29 is:(30+1) x (30-1)sum to differencemakea product= 30² - 1²= 900 - 1= 899
14 and 17
-7 & -14
31, 7, 5
5, 7, 31
Is the sum 31