540.
False, the sum of the angles in a parallelogram is 360 degrees.
The sum of the angles (in degrees) for an n-sided polygon is given by the formula sum = 180 (n-2) For a triangle, n=3 and the sum is 180 (3-2) = 180 For a quadrilateral, n=4 and the sum is 180 (4-2) = 360
No. Only the sum of the measures of the angles of a triangle equal to 180 degrees; in the case of a quadrilateral it amounts to 360 degrees.
The sum of the interior angles of a polygon with n sides is 180(n-2). Setting this equal to 5400 yields 180n - 360 = 5400 or 180 n = 5400 + 360 = 5760 or n = 5760/180 = 32 sides.
It has (7380+360)/180 = 43 sides
If both angles are 180, their sum is 360!If both angles are 180, their sum is 360!If both angles are 180, their sum is 360!If both angles are 180, their sum is 360!
Each angle theta is (n-2)/n) x 180 degrees The sum of all angles is nx theta = (n-2) x 180 sum = 180 n - 360 sum + 360 = 180 n n = (sum + 360)/180 = sum/180 + 2 So you divide sum by 180 then add 2
360 + 180 = 540
360 because ALL quadrilaterals have an angle sum of 360
because INTERIOR ANGLE 180 AND the exterior angle 180 so 180+180=360
The sum of all of the angles in a trapezoid is 360 degrees. The sum of interior angles for an n-sided polygon is equal to 180(n-2) which, in this case, is 180(4-2) = 360.
Sum of exterior angles: 360 degrees Sum of interior angles: 180 degrees The square of its hypotenuse is equal to the sum of its base squared plus its height squared.
No, 180.
There are a number of ways of proving that the sum of the interior angles of a polygon, which has n sides, is (n - 2)*180 degrees.In the case of a quadrangle, n = 2 and so the angle sum is (4 - 2)*180 = 2/180 = 360 deg.
360 degress which is the same as the sum of the interior angles of a quadrilateral. 360 + 8 x 180 = 1800°
180 * n - 360
360 ________________________________________________ Sum of Interior Angles of a Polygon = 180 (n-2) Sum of Exterior Angles of a Polygon = 360 The sum of an angle and an exterior angle of a regular polygon is 360