The sum of two numbers between 20-40 is 58. The difference is 12
58 is 40% of 145
76 + 58 = 134
58 + 17 = 75
Mean of 10 numbers is 58 so sum of 10 numbers is 580. One of them is 40 so the sum of the remaining nine is 540. So mean of the remaining nine is (their sum)/9 = 540/9 = 60 don't know if I'm understanding right but isn't it roughly 3.60
The sum of two numbers between 20-40 is 58. The difference is 12
The sum of 37 and 58 is 95.
58 is 40% of 145
76 + 58 = 134
58 + 17 = 75
Mean of 10 numbers is 58 so sum of 10 numbers is 580. One of them is 40 so the sum of the remaining nine is 540. So mean of the remaining nine is (their sum)/9 = 540/9 = 60 don't know if I'm understanding right but isn't it roughly 3.60
40% of 145= 40% * 145= 0.4 * 145= 58
-24
There are no two consecutive integers that sum to 58. With two consecutive integers, one is even, the other is odd. The sum of an even number and an odd number is odd. 58 is even so cannot be the sum of two consecutive integers.
58/40 = 29/20
The sum is 86
40.