Q: What is the sum of 40?

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The sum of the first 40 odd numbers is 1,600.

58 +40 = 98

1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75

It is 40*41/2 = 820

If your number is 4 times ?, and the sum is 40, your problem would be 40 divided by 4. You'd get 10.

Related questions

The sum of the first 40 whole numbers is 780.

The sum of the first 40 odd numbers is 1,600.

The sum of the first 40 even numbers is 1,640.

58 +40 = 98

20 + 40 = 60

The sum of the first forty positive integers can be calculated using the formula for the sum of an arithmetic series, which is (n/2)(first term + last term) where n is the number of terms. In this case, the sum is (40/2)(1 + 40) = 820.

The sum of the first 40 even positive integers can be equal to 820.

the sum for 20 + 40 + 70 + 80 = 210

When the product of 15 and 40 is divided by the sum of 15 and 45, what is the quotient?

40

40

-39.98