The sum of the numbers between 51 and 150 is equal to 10050 - or 50 x 201 - as there are 50 lots of 201 in the sum.
sum of 150 what? first 150 numbers?
(50 + 15) = 65 (50 x 15) = 750 1/50 + 1/15 = 13/150
To find the sum of all numbers from 51 to 150, we can use the formula for the sum of an arithmetic series: (n/2)(first term + last term), where n is the number of terms. In this case, the first term is 51, the last term is 150, and the number of terms is 150 - 51 + 1 = 100. Plugging these values into the formula, we get (100/2)(51 + 150) = 50 * 201 = 10,050. Therefore, the sum of all numbers from 51 to 150 is 10,050.
There are eight pairs of numbers divisible by three that sum to 150, and 75 is also divisible by three, so: sum = 17 * 75 = 750 + 525 = 1275
The sum of the numbers between 51 and 150 is equal to 10050 - or 50 x 201 - as there are 50 lots of 201 in the sum.
They are: 49+50+51 = 150
50
886
810. All of the integers from -30 to30 cancel each other out by adding a negative to a positive. Then all you need to do is add the integers from 31 to 50. (31 + 32 + ....+50)
sum of 150 what? first 150 numbers?
(50 + 15) = 65 (50 x 15) = 750 1/50 + 1/15 = 13/150
first convert m to cm .1 meter =100 cm now adding 100 cm and 50 cm,we get .150 cm is the sum.
1 2 3 5 6 10 15 25 30 50 75 150 = 372
In 27.5 years. [By the way, I think you mean x+x+95=150.] Let x be the number of years in the future when the sum of their ages will be 150. In x years, the younger person will be 45+x and the older will be 50+x. The sum of their ages will be 150, and the equation to find x is given by: (45+x)+(50+x)=150 Now solve for x: (45+x)+(50+x)=150 95+2x=150 2x=150-95=55 x=55/2=27.5 So the sum of their ages will be 150 in 27.5 years. The younger person will be 45+27.5=72.5 and the older person will be 50+27.5=77.5.
Sum of 150's divisors = 372.
The average of the three numbers is 50, so the other two must be 48 and 52.