It is: 810+50+150 = 1010
The sum of the numbers between 51 and 150 is equal to 10050 - or 50 x 201 - as there are 50 lots of 201 in the sum.
sum of 150 what? first 150 numbers?
(50 + 15) = 65 (50 x 15) = 750 1/50 + 1/15 = 13/150
There are eight pairs of numbers divisible by three that sum to 150, and 75 is also divisible by three, so: sum = 17 * 75 = 750 + 525 = 1275
To find the sum of all numbers from 51 to 150, we can use the formula for the sum of an arithmetic series: (n/2)(first term + last term), where n is the number of terms. In this case, the first term is 51, the last term is 150, and the number of terms is 150 - 51 + 1 = 100. Plugging these values into the formula, we get (100/2)(51 + 150) = 50 * 201 = 10,050. Therefore, the sum of all numbers from 51 to 150 is 10,050.
The sum of the numbers between 51 and 150 is equal to 10050 - or 50 x 201 - as there are 50 lots of 201 in the sum.
They are: 49+50+51 = 150
50
886
sum of 150 what? first 150 numbers?
810. All of the integers from -30 to30 cancel each other out by adding a negative to a positive. Then all you need to do is add the integers from 31 to 50. (31 + 32 + ....+50)
(50 + 15) = 65 (50 x 15) = 750 1/50 + 1/15 = 13/150
first convert m to cm .1 meter =100 cm now adding 100 cm and 50 cm,we get .150 cm is the sum.
1 2 3 5 6 10 15 25 30 50 75 150 = 372
In 27.5 years. [By the way, I think you mean x+x+95=150.] Let x be the number of years in the future when the sum of their ages will be 150. In x years, the younger person will be 45+x and the older will be 50+x. The sum of their ages will be 150, and the equation to find x is given by: (45+x)+(50+x)=150 Now solve for x: (45+x)+(50+x)=150 95+2x=150 2x=150-95=55 x=55/2=27.5 So the sum of their ages will be 150 in 27.5 years. The younger person will be 45+27.5=72.5 and the older person will be 50+27.5=77.5.
Sum of 150's divisors = 372.
The average of the three numbers is 50, so the other two must be 48 and 52.